[英]How to print a message if the do while loop condition is not met
How would I print a message saying "Error: you have to enter a number between 0 and 5", then allowing the user to input again 我将如何打印一条消息,指出“错误:您必须输入0到5之间的数字”,然后允许用户再次输入
int number;
do
{
String textinput = JOptionPane.showInputDialog("give me a number between 0 and 5");
number = Integer.parseInt(textinput);
} while (!(number >= 0 && number <= 5));
The simplest method which alters your original code the least is as follows: 最少更改原始代码的最简单方法如下:
int number;
do {
String textinput = JOptionPane.showInputDialog("give me a number between 0 and 5");
number = Integer.parseInt(textinput);
if((number < 0) || (number > 5) {
//show error message
continue; //continue isn't absolutely necessary here, but perhaps for readability
}
} while (!(number >= 0 && number <= 5));
Although I find this a little clunky and redundant, you're essentially checking the same condition twice. 尽管我发现这有点笨拙和多余,但是您实际上要检查两次相同的条件。 I'd go with a method more like the following: 我会使用更类似于以下的方法:
int number;
String textinput = JOptionPane.showInputDialog("give me a number between 0 and 5");
while(true) {
number = Integer.parseInt(textinput);
if((number >= 0 && number <= 5)) {
//show error message and prompt for another input
contine; //As with before, continue isn't necessary here, but could add readability
} else /*input was good*/ { break; /*exit while loop*/ }
}
you could do it like this. 你可以这样 I used a regular expression to prevent a NumberFormatExcption. 我使用正则表达式来防止NumberFormatExcption。
int number = -1;
do
{
String textinput = JOptionPane.showInputDialog("give me a number between 0 and 5");
if( textinput.match("0*[0-5]") {
number = Integer.parseInt(textinput);
}
else {
System.out.println("Error");
}
} while (!(number >= 0 && number <= 5));
String textinput = JOptionPane.showInputDialog("give me a number between 0 and 5");
int number = Integer.parseInt(textinput);
while (!(number >= 0 && number <= 5)) {
textinput = JOptionPane.showInputDialog("Your number must be between 0 and 5!");
number = Integer.parseInt(textinput);
}
// do stuff
I believe this would be the least redundant and most readable way to write this: 我相信这将是编写此代码的最少冗余和最易读的方式:
int number;
while ((number = requestNumber()) < 0 || number > 5) {
// Show your prompt
}
Declare this method somewhere: 在某处声明此方法:
private int requestNumber() {
try {
String textinput = JOptionPane.showInputDialog("give me a number between 0 and 5");
return Integer.parseInt(textinput);
} catch(NumberFormatException nfe) {
return -1;
}
}
This is another option: 这是另一个选择:
boolean valid;
int number;
do {
String textinput = JOptionPane.showInputDialog("give me a number between 0 and 5");
number = Integer.parseInt(textinput);
if (number >= 0 && number <= 5) {
valid = true;
} else {
// Show your message here
valid = false;
}
} while (!valid);
It would avoid the recalculation of number >= 0 && number <= 5
offered by the solutions of most of the answers. 它将避免大多数答案的解决方案提供的number >= 0 && number <= 5
的重新计算。
The code in this answer was not tested 此答案中的代码未经测试
int number;
if(nummber>0 && number<5)
{
do
{
String textinput = JOptionPane.showInputDialog("give me a number between 0 and 5");
number = Integer.parseInt(textinput);
} while (!(number >= 0 && number <= 5));
}
else
{
System.out.println("you have to enter a number between 0 to 5");
}
int number;
Boolean bolContinue = true;
do
{
String textinput = JOptionPane.showInputDialog("give me a number between 0 and 5");
number = Integer.parseInt(textinput);
if (!(number >= 0 && number <= 5)) {
//Log here
bolContinue = false;
}
} while (bolContinue);
It should be as simple as that. 它应该就是那样简单。
int number;
do
{
String textinput = JOptionPane.showInputDialog("give me a number between 0 and 5");
number = Integer.parseInt(textinput);
if(!(number >= 0 && number <= 5))
{
System.out.println("Error: you have to enter a number between 0 and 5");
}
} while (!(number >= 0 && number <= 5));
Like this: 像这样:
int number;
do
{
String textinput = JOptionPane.showInputDialog("give me a number between 0 and 5");
number = Integer.parseInt(textinput);
if ( number > 5 || number < 0)
{
System.out.println("Please enter number between 0 to 5");
return;
}
} while (!(number >= 0 && number <= 5));
}
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