Flask Restful API网址

Question

I am using Flask-RESTful( http://flask-restful.readthedocs.org/en/latest/index.html ) in my project. Afrer reading some examples I understood that I will have only get, post, update etc methods in my Resource class. How can I make my own Resource class method with a unique url like it was in Flask with @app.route() decorator? Thanks.

Answer 1

Look at quick start ( A Minimal API , Resourceful Routing and etc.):

api.add_resource(HelloWorld, '/')

api.add_resource(TodoSimple, '/<string:todo_id>')

Answer 2

I hope it helps

@app.route('/', methods=['GET', 'POST'])
def index():
    if request.method == 'GET':
        pass
    elif request.method == 'POST':
        pass
    else:
        pass