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将会议记录转换为人类可读的格式

[英]Convert minutes into a human readable format

quick question.快速提问。

Is there a smarter/sleeker way to convert minutes into a more readable format, showing only the most significant digit?是否有更智能/更流畅的方式将分钟转换为更易读的格式,仅显示最高有效数字?

I'm using Android Studio's Java.我正在使用 Android Studio 的 Java。

public String MinutesToHumanReadable(Long minutes) {

...

}

ie IE

2 mins = "2 mins"
45 mins = "45 mins"
60 mins = ">1 hr"
85 mins = ">1 hr"
120 mins = ">2 hrs"
200 mins = ">3 hrs"
1500 mins = ">1 day"

My code is very cumbersome, sloppy, and somewhat unreadable.我的代码非常繁琐、草率,而且有些不可读。

public String MinutesToHumanReadable(long minutes) {
    String sReturn = "";

    if (minutes > 515600) {
        sReturn = "> 1 yr";

    } else if (minutes > 43200) {
        sReturn = (minutes / 43200) + " mths";

    } else if (minutes > 10080) {
        sReturn = (minutes / 10080) + " wks";

    } else if (minutes > 1440) {
        sReturn = (minutes / 1440) + " days";

    } else if (minutes > 60) {
        sReturn = (minutes / 60) + " hrs";

    } else {
        //<60
        sReturn = minutes + " mins";

    }

    return sReturn;
}

Many thanks, J非常感谢,J

Well it is possible, I figure it out and I am proud of it! 嗯,这是有可能的,我明白了,我为此感到自豪! :) Note that you can easily add any other value without changing the method itself, only by changing values in these two arrays. :)请注意,只需更改这两个数组中的值,即可轻松添加任何其他值而无需更改方法本身。 For example, if "years" are not enough for you, you can add "decades" and "centuries"... 例如,如果“年”对你来说还不够,你可以添加“几十年”和“几个世纪”......

This code also adding "s" letter at the end, if you have more than 1 of output value. 如果输出值超过1,此代码也会在末尾添加“s”字母。

public class SuperMinutesChangerClass {
    public static int[] barriers = {1, 60, 60*24, 60*24*7, 60*24*365, Integer.MAX_VALUE};
    public static String[] text = {"min", "hr", "day", "week", "year"};

    public static String minutesToHumanReadable(int minutes){
        String toReturn = "";
        for (int i = 1; i < barriers.length; i++) {
            if (minutes < barriers[i]){
                int ammount = (minutes/barriers[i-1]);
                toReturn = ">" + (ammount) + " " + text[i-1];
                if (ammount > 1){
                    toReturn += "s";
                }
                break;
            }
        }
        return toReturn;
    }         
}

Sample input : 样本输入:

    public static void main(String[] args) {
        System.out.println(minutesToHumanReadable(10));
        System.out.println(minutesToHumanReadable(60));
        System.out.println(minutesToHumanReadable(61));
        System.out.println(minutesToHumanReadable(121));
        System.out.println(minutesToHumanReadable(8887));
        System.out.println(minutesToHumanReadable(9999743));
    }  

Output is : 输出是:

>10 mins
>1 hr
>1 hr
>2 hrs
>6 days
>19 years

I would use some dummy if/else if/else statements : 我会使用一些虚拟的if/else if/else语句:

public static String convert(int minutes) {
  if(minutes < 60) {
    return String.format("%d mins", minutes);
  } else if(minutes < 1440) { //1 day = 1440 minutes
    return String.format("%d hrs, %d mins", minutes/60, minutes%60);
  } else {
    return String.format("%d days", minutes / 1440);
  }
}

Test 测试

System.out.println(convert(84));

Output : 输出:

1 hrs, 24 mins 1小时24分钟

maybe this helps you 也许这有助于你

private static final int MINUTES_PER_HOUR = 60;
private static final int MINUTES_PER_DAY = MINUTES_PER_HOUR * 24;

public String minutesToHumanReadable(long minutes) {
    if (minutes > MINUTES_PER_DAY) {
        return String.format("> %d days", minutes / MINUTES_PER_DAY);
    } else if (minutes > MINUTES_PER_HOUR) {
        return String.format("> %d hours", minutes / MINUTES_PER_HOUR);
    }

    return String.format("%d minutes", minutes);
}

Improving answer by Joshua Pinter and Arnaud Denoyelle. Joshua Pinter 和 Arnaud Denoyelle 改进了答案。

    fun convertMinutesToHumanReadable(minutes: Int, context: Context): String {
    return if (minutes < 60) {
        "$minutes ${context.resources.getQuantityString(R.plurals.minutes_abbrev, minutes)}"
    } else if (minutes % 60 == 0 && minutes < 1440) {
        val hours1 = minutes / 60
        "$hours1 ${context.resources.getQuantityString(R.plurals.hours_abbrev, hours1)}"
    } else if (minutes < 1440) {
        val hours1 = minutes / 60
        val minutes1 = minutes % 60
        "$hours1 ${
            context.resources.getQuantityString(
                R.plurals.hours_abbrev, hours1
            )
        }, $minutes1 ${
            context.resources.getQuantityString(
                R.plurals.minutes_abbrev, minutes1
            )
        } "
    } else if (minutes % 1440 == 0) {
        val days1 = minutes / 1440
        "$days1 ${context.resources.getQuantityString(R.plurals.days, days1)}"
    } else {
        val days1 = minutes / 1440
        "$days1 ${context.resources.getQuantityString(R.plurals.days, days1)}, ".plus(
            convertMinutesHumanReadable(minutes % 1440, context)
        )
    }
}

And add this to res/values/strings.xml file并将其添加到 res/values/strings.xml 文件

<plurals name="minutes_abbrev">
        <item quantity="one">min</item>
        <item quantity="other">mins</item>
    </plurals>
    <plurals name="hours_abbrev">
        <item quantity="one">hr</item>
        <item quantity="other">hrs</item>
    </plurals>
    <plurals name="days">
        <item quantity="one">day</item>
        <item quantity="other">days</item>
    </plurals>

In this way it will show singular or plural depending on the amount and also supports values larger than one day.通过这种方式,它将根据数量显示单数或复数,并且还支持大于一天的值。 For example: 2 days, 8 hrs, 23 mins or 1 day, 2 hrs, 1 min例如:2 天 8 小时 23 分钟或 1 天 2 小时 1 分钟

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