[英]Postrgresql One-To-Many with MVC3 and jTable
I'm a newbie in MVC apps, and I've encountered a very specific problem. 我是MVC应用程序的新手,并且遇到了非常具体的问题。 Thing is, I have 2 classes: "Paciente" and "Analises". 问题是,我有2个班级:“ Paciente”和“ Analises”。
public class Paciente
{
public virtual Guid PacienteID { get; set; }
public virtual string Nome { get; set; }
public virtual string Sexo { get; set; }
public virtual DateTime DataDeNasc { get; set; }
public virtual int IdadeDiag { get; set; }
public virtual IList<Analises> analises { get; set; }
}
public class Analises
{
public virtual Guid AnaliseID { get; set; }
// some analysiss values
public virtual decimal afp { get; set; }
public virtual decimal hemoglobina { get; set; }
public virtual DateTime DataDaAnalise { get; set; }
public virtual Paciente pac { get; set; }
}
So, a Patient has many Analysis, and each Analysis has one Patient (on-to-many). 因此,一个病人有很多分析,并且每个分析都有一个病人(多对多)。
I have mapped this with NHIbernate and FluentNHibernate: 我已经用NHIbernate和FluentNHibernate映射了这个:
public PacienteMap()
{
Table("pacientes");
Id(x => x.PacienteID).GeneratedBy.Guid();
Map(x => x.Nome);
Map(x => x.Sexo);
Map(x => x.DataDeNasc).CustomType("Date");;
Map(x => x.IdadeDiag);
HasMany(m => m.analises).Not.KeyNullable().Fetch.Join().KeyColumn("pacienteid");
}
public AnalisesMap()
{
Table("analises");
Id(x => x.AnaliseID).GeneratedBy.Guid();
Map(x => x.afp);
Map(x => x.hemoglobina);
Map(x => x.DataDaAnalise).CustomType("Date");
References(x => x.pac).ForeignKey("pacienteid").Not.Nullable();
}
My problem is that I'm using jTable to show this. 我的问题是我正在使用jTable来显示此内容。 I want to see a list of Patients (and it works), and then, a list of analysis for each patient (doesn't work!) 我想查看“患者列表”(并且有效),然后查看每个患者的分析列表(“无效”!)
My Controller goes like this: 我的控制器如下所示:
[HttpPost]
public JsonResult AnalisesList(Guid pacienteId)
{
try
{
var list_analises = AnalisesRepository.GetPacienteAnalises(pacienteId);
var all_analises = Mapper.Map<IEnumerable<Analises>, IEnumerable<AnalisesView>>(list_analises);
List<AnalisesView> analises = all_analises.ToList();
return Json(new { Result = "OK", Records = analises });
}
catch (Exception ex)
{
return Json(new { Result = "ERROR", Message = ex.Message });
}
}
I am also using automapper to go from the Object Views from Database Objects. 我还使用自动映射器从数据库对象的对象视图中进行操作。
So, rigth now, my analysis list does not show! 因此,很遗憾,我的分析列表未显示! I don't know why. 我不知道为什么 The GetPacienteAnalises is like: GetPacienteAnalises类似于:
public IList<T> GetPacienteAnalises (Guid pacienteId)
{
using (ISession session = SessionManager.OpenSession())
{
using (ITransaction transaction = session.BeginTransaction())
{
return session.CreateCriteria(typeof(T)).Add(Restrictions.Eq("pacienteid", pacienteId)).List<T>();
}
}
}
So, I think everything is Okay... But I keep receiving a "could not resolve property: pacienteid of: Infraestrutura.Models.Analises". 因此,我认为一切都很好...但是我一直收到“无法解析属性:的理由:Infraestrutura.Models.Analises”。
Your problem is in this line: 您的问题在这一行:
return session.CreateCriteria(typeof(T))
.Add(Restrictions.Eq("pacienteid", pacienteId))
.List<T>();
I assume that T
in this case is Analises
. 我假设在这种情况下T
是Analises
。 Analises
does not have a property named pacienteid
. Analises
没有名为pacienteid
的属性。 Instead, it has a property named pac
. 相反,它具有一个名为pac
的属性。 Replace "pacienteid"
with "pac.PacienteID"
. 将"pacienteid"
替换为"pac.PacienteID"
。 The fields that you use when creating the criteria should be the property names, not the column names. 创建条件时使用的字段应该是属性名称,而不是列名称。
return session.CreateCriteria(typeof(T))
.Add(Restrictions.Eq("pac.PacienteID", pacienteId))
.List<T>();
If you were filtering by some column other than Paciente
's primary key, Nome
for example, then a join would be necessary. 如果您按除Paciente
的主键(例如Nome
之外的其他列进行过滤,则必须进行Paciente
。 In that case, you would do something like: 在这种情况下,您将执行以下操作:
session.CreateCriteria(typeof(T))
.CreateAlias("pac", "p") // CreateAlias performs an inner join
.Add(Expression.Eq("p.Nome", name))
.List<T>()
But no join is needed to get to pac.PacienteID
. 但是不需要pac.PacienteID
即可到达pac.PacienteID
。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.