[英]how to simultaneously update two div using jquery ajax?
I am designing a like and dislike feature. 我正在设计一个喜欢和不喜欢的功能。 But problem arise when i update my like as the same time it must update the dislike
div
too. 但是问题是,当我同时更新我的喜欢时,它也必须更新不喜欢的
div
。
this is my .js for dislike: 这是我不喜欢的.js:
$('.dislike').click(function(e) {
dislike = $(this);
to_dislike= dislike.data('val');
$.ajax({
type : 'POST',
url : '<?php echo site_url('/url.php');?>',
data : 'dislikes='+to_dislike,
dataType : 'text',
success : function(data){
$("#dislike_"+to_dislike).html(data);
},
error : function(){
$("#dislike_"+to_dislike).html('Sorry');
}
});
});
Its working good. 它的工作很好。 but i want to modify it in such a way that it should simultaneously update my div:
但我想以一种可以同时更新我的div的方式对其进行修改:
<div id='like'></div>
Here is my HTML : 这是我的HTML:
<table>
<tr>
<td> <button class="like"></button></td>
<td> <button class="dislike"></button></td>
</tr>
<tr>
<td>LIKE : <div id='like'></div></td>
<td> Dislike : <div id='dislike'></div></td>
</tr>
</table>
EDIT: 编辑:
Update: I have to fetch data about like and dislike at same time and then put that data in two different div's. 更新:我必须同时获取有关喜欢和不喜欢的数据,然后将该数据放入两个不同的div中。 There is a table with
like
and dislike
column. 有一个带有“
like
和“ dislike
列的表。 On like i update my likes. 在喜欢我更新我的喜欢。 But if a person dislike after liking a particular post then dislike is updated to +1 and like is updated to -1.
但是,如果某个人在喜欢某个特定帖子后不喜欢,那么不喜欢将更新为+1,喜欢将更新为-1。
please help.. 请帮忙..
If i am getting you right then u want to get data from database and display it in two different div using one jquery call. 如果我说对了,那么您想从数据库中获取数据并使用一个jquery调用将其显示在两个不同的div中。
Why don't you concatenate the string with some symbol like $
and then when echo it. 为什么不使用
$
等符号将字符串连接起来,然后在回显时呢? On Success just filter the data and put it in different div. 成功后,只需过滤数据并将其放在不同的div中即可。 Hope it helped.
希望能有所帮助。 :)
:)
If I understand correctly you just want to update the number of likes and dislikes in your divs. 如果我理解正确,那么您只想更新div中喜欢和不喜欢的次数。
$('.dislike').click(function(e) {
dislike = $(this);
to_dislike= dislike.data('val');
$.ajax({
type : 'POST',
url : '<?php echo site_url('/url.php');?>',
data : 'dislikes='+to_dislike,
dataType : 'text',
success : function(data){
var dislike = parseInt($("#dislike").html());
var like = parseInt($("#like").html());
if ( dislike >= 0 && like >= 0) {
$("#dislike").html(dislike + 1);
$("#like").html(like - 1);
}
}
});
});
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