在bash中重复printf格式

Question

I am trying to printf an array in bash, whose number of element is previously unknown. so, the goal is to have something like:

printf  "latc= ${#latc[@]}%s\n" ${latc[@]}

but it does not seem to be possible. I even tried solution of this thread as

for x in "${latc[@]}"
do
  printf " %s:%s\n" ${x}
done

, but I am not getting what I want.

currently I am working with:

printf  "       latc="
echo ${latc[@]}

clearly not an elegant method of doing thigs. Any help please?

Answer 1

It looks like you want

printf "latc=%s\n" "${latc[*]}"

Quoting ${latc[*]} produces a single string in which the elements of latc are joined using the first character of IFS (by default, a space). Quoting ${latc[@]} induces a special expansion that produces one word for each element of the array. There is no way to indicate a repeated placeholder in the format string as you seemed to be trying with ${#latc[*]}%s .

Answer 2

您可以将数组打印为：

printf "%s\n" "${latc[@]}"