在python中将输入作为以空格分隔的整数

Question

So I have gotten the program to work, my problem so far is that my solution requires that the output look like this [44, 76, 34, 98, 1, 99] but I keep getting ['1', '2', '3', '5', '6', '7'] if my input was 44 76 44 34 98 34 1 44 99 1 1 1

Trying to convert the final solution into an int and then back into a string does not work, I still end up with quotations.

The point of the code BTW is to remove duplicates from a given input and print it out in a list

def eliminateDuplicates(lst): 
    newlist = []
    for number in lst:
        if number not in newlist:
            newlist.append(number)
    return newlist

def main():
    numbers =(input("Enter numbers separated by space: "))
    x = ((numbers.split()))
    print("The distinct numbers are: ", (eliminateDuplicates(x))) 

main()

Answer 1

In the first line we store the input in d. In the second line we convert d into set() and back to list(). In the third line we map() d to integer.

d = raw_input("Enter Numbers: ").split()
d = list(set(d))
d = map(int, d)
print d

Answer 2

尝试这个：

print("The distinct numbers are: ", map(int, eliminateDuplicates(x)))

Answer 3

If the parameter lst is supposed to be a list , why don't you enter a list as input? (Instead of numbers separated by space). Then you can ommit the split stuff:

def eliminateDuplicates(lst): 
    newlist = []
    for number in lst:
        if number not in newlist:
            newlist.append(number)
    return newlist

def main():
    numbers =(input("Enter numbers as a list: "))
    print("The distinct numbers are: ", (eliminateDuplicates(numbers))) 
main()

Answer 4

Hope this helps:

from collections import OrderedDict
def eliminateDuplicates(lst): 
    newlist = [int(x) for x in lst]
    newlist = list(OrderedDict.fromkeys(newlist))
    return newlist

def main():
    numbers =(input("Enter numbers separated by space: "))
    x = ((numbers.split()))
    print("The distinct numbers are: ", (eliminateDuplicates(x))) 
main()

Answer 5

The reason you're getting quotation marks around your numbers when you print them is because you're printing a list , which implicitly converts the list to a string (using str ). The list type's __str__ method uses the repr of each of its list items. The repr of a string puts quotes around it.

There's a good reason for this. repr is supposed to be a computer-friendly represnetation of an object. If possible, it should create a duplicate of the object when eval ed. If lists or strings behaved differently when printed, a list like ["foo", "bar, baz", "quux"] would have an ambiguous repr .

Converting the input values to integers (as other answers have suggested) is one solution, but not a necessary one for this task. Your deduplicating function works just fine with lists of strings. If the output formatting is the only issue, you can str.format and str.join to create an output string in the form you want from your list of strings, rather than printing the list directly. For instance:

print("The distinct numbers are: [{}]".format(", ".join(eliminateDuplicates(x)))

Answer 6

Just replace this line of your code.

x =[ int(num) for num in numbers.split(' ') if len(num)>0 ]

Everything will work fine.
After changing this line, your whole code will look like below

def eliminateDuplicates(lst): 
newlist = []
for number in lst:
    if number not in newlist:
        newlist.append(number)
return newlist

def main():
    numbers =(input("Enter numbers separated by space: "))
    x =[ int(num) for num in numbers.split(' ') if len(num)>0 ]
    print("The distinct numbers are: ", (eliminateDuplicates(x))) 

main()

Output will be

Enter numbers separated by space: 44 76 44 34 98 34 1 44 99 1 1 1
The distinct numbers are:  [44, 76, 34, 98, 1, 99]

At the time of reading space separated inputs in python , they are treated as string so you need to convert them into integer. strings can be converted into integers in many ways like below
Using list comprehension

numbers = [ int(num) for num in input().split(' ') if len(num)>0 ]

Using filter and map function

numbers = list(map(int,filter(lambda x : len(x)>0,input().split(' '))))