为什么使用可迭代的最后一个maxlen项初始化python deque？

Question

I was learning how to use deque. Here's what I did:

>>> d = deque([1,2,3,4,5,6], maxlen=3)

I expected that d would contain [1,2,3]. But instead I got:

>>> d
deque([4, 5, 6], maxlen=3)

Isn't this counterintuitive?

Answer 1

From docs :

Once a bounded length deque is full, when new items are added, a corresponding number of items are discarded from the opposite end . Bounded length deques provide functionality similar to the tail filter in Unix. They are also useful for tracking transactions and other pools of data where only the most recent activity is of interest.

So, your code is equivalent to:

>>> from collections import deque
>>> d = deque(maxlen=3)
>>> for i in range(1, 7):
...     d.append(i)
...     print d
...     
deque([1], maxlen=3)
deque([1, 2], maxlen=3)
deque([1, 2, 3], maxlen=3)
deque([2, 3, 4], maxlen=3)
deque([3, 4, 5], maxlen=3)
deque([4, 5, 6], maxlen=3)

Answer 2

The official doc mentioned this clearly:

Once a bounded length deque is full, when new items are added, a corresponding number of items are discarded from the opposite end.

Answer 3

Not at all, from the docs:

"Returns a new deque object initialized left-to-right (using append()) with data from iterable"

I have mainly used deque objects as buffers for the most recent items. So all the users last 100 actions for example.

Answer 4

It is a design decision. It is more practical to keep more recent elements in the queue. The older are just being poped out from the other end.