如何使用请求捕获发布请求的结果页面？

Question

I'm using Python with Requests and I'm trying to send data to a form for a website that shortens links. I want to store the link to their shortened link in a variable once I use requests.post.

I've read about status codes, but I don't quite know how to used them. Here's what the form for input looks like.

<form method="post" action="paste.php">
    <div class="row">
        <div class="12u">
            <input type="text" name="name" id="name" placeholder="Name of paste" />
        </div>
    </div>
    <div class="row">
        <div class="12u">
            <textarea name="paste" id="paste" placeholder="Paste contents"></textarea>
        </div>
    </div>
    <div class="row">
        <div class="12u">
            <a type="submit" class="button form-button-submit">Upload</a>
            <a href="#" class="button button-alt form-button-reset">Undo</a>
        </div>
    </div>
</form>

Here's what I have so far.

def create_paste(url):
    title = 'title' # Define your title.
    paste = 'paste' # Define your paste content.

    try:
        durk = requests.post(url, data={'name': title, 'paste': paste})

        if durk.status_code == 302:
            print('Pasted!')
        else:
            print('Not pasted!')
    except:
        raise

How can I go about doing this? Thanks.

EDIT: Solved the problem by re-reading the Requests documentation. If I allow redirects and use r.url, I can show the paste link.

def derp():
    title = 'adsfjkl' # Define your title.
    paste = 'asdfasdhfasdflkjashdfkjasht' # Define your paste content.

    r = requests.post('http://website.com/paste.php', data={'name': title, 'paste': paste}, allow_redirects=True)

    if r.status_code == 200:
        print('Pasted! %s' % (r.url))
    else:
        print('Not pasted!')

    print r.url

Answer 1

The easiest way would be to indeed use Requests.post and then pass this post result to beautifulsoup and parse the result.

For instance:

import request
from bs4 import BeautifulSoup as BS

response = request.get('http://stackoverflow.com/') 
bs = BS(response.text)

//do some parsing using beautifulsoup to get the link