[英]'If' 'else' statement in Perl
I have written code which yield a group of words我写了产生一组单词的代码
my $uptime = `command | sed -n "xp" | cut -d" " -fx`;
The above command gives me the below word.上面的命令给了我下面的词。
not running
I would like to use this word in an if statement like below:我想在如下if语句中使用这个词:
if ($uptime = $not){
$run = `command`;
$start = `start`;
I have declared a variable $not
and put "not running"
in it.我已经声明了一个变量
$not
并在其中放置了"not running"
。 Though the script is working, it is doing the opposite, when the program is running.尽管脚本正在运行,但在程序运行时却相反。 The below command gives a different word which (like "ok") is not in the variable
$not
, but the script is restarting the program.下面的命令给出了一个不同的词(如“ok”)不在变量
$not
,但脚本正在重新启动程序。
#!/usr/bin/perl
use warnings;
use strict;
$not = "not running";
$uptime = `command | sed -n "xp" | cut -d" " -fx`;
if ($uptime = $not){
# If not running, the program then executes the below, else do nothing
$run = `cp /home/x`;
$start = `start`;
}
'if ($uptime = $not)' and 'if ($uptime eq $not)'
are two different things.是两个不同的东西。
eq
is string comparison operator so it will return 1 when the comparison is equal and ''
when the condition does not satisfy, whereas if ($uptime = $not)
will return true when $not
evaluates to true because you are assigning one variable to another using assignment operator =
. eq
是字符串比较运算符,因此当比较相等时它将返回 1,当条件不满足时返回''
,而if ($uptime = $not)
将在$not
评估为真时返回真,因为您将一个变量分配给另一个使用赋值运算符=
。 So please change your code.所以请更改您的代码。
your condition will look like the following .
$uptime=chomp($uptime);
if ($uptime eq $not){
//your code
}
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