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创建函数时出现MYSQL 1064错误

[英]Getting a MYSQL 1064 error when creating a function

DELIMITER $$

    CREATE FUNCTION nameOfFunct(intIn int)
    RETURN int
    BEGIN
        DECLARE intOut INT;
        SET intOut = SELECT count(*)
            FROM tableToTakeFrom
            WHERE columToCompareTo = intIn;

        RETURN intOut;
    END;
        $$

DELIMITER;

If I try to run this all I get is: 如果我尝试运行此命令,我将得到的是:

SQL Error (1064): You have an error in your SQL syntax; SQL错误(1064):您的SQL语法有错误; check the manual that corresponds to your MySQL server version for the right syntax to use near 'RETURN int 检查与您的MySQL服务器版本相对应的手册以获取正确的语法,以在'RETURN int附近使用
BEGIN 开始
DECLARE intOut INT; DECLARE intOut INT;
SET intOut = select count(' at line 2 SET intOut =选择count('在第2行

A couple of changes to resolve the problem: 为解决该问题进行了一些更改:

DELIMITER $$

CREATE FUNCTION nameOfFunct(intIn INT)
-- RETURN INT
RETURNS INT
BEGIN
    DECLARE intOut INT;
    /*SET intOut = SELECT COUNT(*)
        FROM tableToTakeFrom
        WHERE columToCompareTo = intIn;*/
    SET intOut = (SELECT COUNT(*)
        FROM tableToTakeFrom
        WHERE columToCompareTo = intIn);
    RETURN intOut;
END $$

DELIMITER ;

Defining the return type is done by the RETURNS keywrod, not the RETURN keyword: 定义返回类型是通过RETURNS键来完成的,而不是RETURN关键字:

CREATE FUNCTION nameOfFunct(intIn int)
RETURNS int
BEGIN
    DECLARE intOut INT;
    SET intOut = SELECT count(*) 
                 FROM   tableToTakeFrom
                 WHERE  columToCompareTo = intIn;
    RETURN intOut;
END;

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