[英]Segmentation Fault - Transpose of a Matrix - C
I have a segmentation fault error on the following code: 我在以下代码上出现细分错误错误:
struct matrix {
int nl, nc ;
int** mat ;
};
Matrix* initMatrix (int nlines, int ncol) {
struct matrix* mat ;
mat = (struct matrix*)malloc(sizeof(struct matrix)) ;
mat->nl = nlines ;
mat->nc = ncol ;
int i ;
mat->mat = (int **)malloc((mat->nl)*sizeof(int *)) ;
for (i=0;i<(mat->nl); i++) {
mat->mat[i] = (int*)malloc((mat->nc)*sizeof(int)) ;
}
return mat ;
}
Matrix* transp (Matrix* mat) {
int i, j;
int linesTrp = mat->nc ;
int colTrp = mat->nl ;
Matrix* trp = initMatrix (linesTrp, colTrp) ;
for (i=0; i<(linesTrp); i++) {
for (j=0; j<(colTrp); j++) {
trp->mat[j][i] = mat->mat[i][j] ;
}
}
return trp;
}
Apparently, the program gives me the segmentation fault message when it reaches this line: 显然,该程序在到达以下行时会给出分段错误消息:
for (j=0; j<(colTrp); j++) {
Please, if anyone can help me, I would appreciate. 请,如果有人可以帮助我,我将不胜感激。 Also, sorry for eventual bad english (I'm from Brazil) 另外,对您最终的英语不好也感到抱歉(我来自巴西)
Try: 尝试:
Matrix* transp (Matrix* mat) {
int i, j;
int linesTrp = mat->nc ;
int colTrp = mat->nl ;
Matrix* trp = initMatrix (colTrp, linesTrp) ; //edited
for (i=0; i<(linesTrp); i++) {
for (j=0; j<(colTrp); j++) {
trp->mat[j][i] = mat->mat[i][j] ; //edited
}
}
return trp;
}
Paul Draper, you almost right. 保罗·德雷珀(Paul Draper),您说得对。 I think, correct code should look like this: 我认为,正确的代码应如下所示:
Matrix* transp (Matrix* mat) {
int i, j;
int linesTrp = mat->nc ;
int colTrp = mat->nl ;
Matrix* trp = initMatrix (linesTrp, colTrp) ; // was correct originally
for (i=0; i< colTrp; i++) { // edited to correctly address mat->mat
for (j=0; j< linesTrp; j++) { // edited to correctly address mat->mat
trp->mat[j][i] = mat->mat[i][j] ; //edited
}
}
return trp;
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.