将“ 9632580147”转换为int时出现Java分析错误

Question

In my java code, I have a string 9632580147 , and when I convert it into a int, using this code:

            try{  
                sNumberInt = Integer.parseInt(sNumber);  
            } catch(NumberFormatException nfe) {  
                Log.d("NUMBER", nfe.getMessage());
                return;  
            } 

It goes into the catch block saying Invalid int: "9632580147" ... Does anyone know how to fix this?

Thanks

Answer 1

Max value of int is 2147483647 and you are trying to pass 9632580147 which is greater. Try maybe Long.parseLong(sNumber)

Answer 2

When you type

int sNumber = 9632580147;

into your code, the compiler will tell you:

The literal 9632580147 of type int is out of range

The reason is that your number is too big to fit into an int, use a long instead.

Answer 3

似乎您传递的值大于32位：9632580147 = 1000111110001001011000001000110011（34位）

Answer 4

Integer最大值为2147483647。如果要分割该数字，则需要将其解析为Long 。

Answer 5

The maximum value of the integer in Java is 2147483647 while your input 9632580147 is greater. Instead, use a long data type:

long sNumberLong = Long.parseLong(sNumber);