是否可以在 Python 中针对 XSD 1.1 验证 XML 文件？

Question

I want validate an XML file against an XSD file using lxml.XMLSchema. But the problem is the XSD is in 1.1. So it doesn't work.

This is a part of the XML:

<?xml version="1.0" encoding="UTF-8"?>
<dictionary xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
            xsi:noNamespaceSchemaLocation="!!assert.xsd">
  <SizeType>10</SizeType>
</dictionary>

And this is its XSD file:

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
           elementFormDefault="qualified">
  <xs:element name="SizeType">
    <xs:simpleType>
      <xs:restriction base="xs:integer">
        <xs:assertion test="$value = 10"/>
      </xs:restriction>
    </xs:simpleType>
  </xs:element>
</xs:schema>

So, is it possible to validate an XML file against a XSD file that uses xs:assertion statements (1.1)?

I think this question is closely related to this: lxml with schema 1.1

Answer 1

xmlschema (1.0.14+) supports XSD 1.1

https://pypi.org/project/xmlschema

Answer 2

As of early November 2013, only the following XML processors support XSD 1.1:

• Xerces-J with PsychoPath XPath 2.0
• Saxon EE
• Altova

There is no XML parser written in Python that validates against XSD 1.1 yet.