Boost.Python-是否不对C ++使用任何Boost？

Question

I have developed a library in C++ (native) and have not used boost in any of the bindings.

I'm using Python to create a Wrapper for this library so it can work client-side. After looking at all of the available options to me, it was decided that boost.python was the chosen method. The question is whether or not I can use boost.python for the Python/client side of this, even though I did not use boost in any of the C++ implementation?

Also, assume that my library is called myLib is it therefore possible to have:

myLib.Vector() where I can push values to it? ie vect = myLib.Vector(1, 2, 3, 4, 5)

Without having to create a class called Vector inside of the C++ library?

Any help would be greatly appreciated

Answer 1

You can use boost.python and ignore the rest of boost.

You can explicitely instantiate a vector template specialization in a .cpp file

template class vector<int>;

and later expose it in your python code:

class_<...>("Vector").def(...);

This way it should work.