Windows批处理文件中的Javac和Java命令

Question

I normally compile things through the command line using:

javac -classpath . Test.java

Similarly, I run them through:

java -classpath . Test

I'm now attempting to save myself the trouble of typing these out every time through batch files. I have attempted to do so through another question from here:

Creating a batch file, for simple javac and java command execution

I've also tried my own way:

cmd.exe
@echo off
javac -classpath . Test.java

Still no luck, however. I have checked that my PATH environment variable is correctly pointing to the latest version of jdk and as I've said, I can compile just fine directly through command line. Upon running the batch file, I just get the command prompt with no error; as if there was nothing under cmd.exe. Could anyone lend a helping hand and slap some sense into me?

Answer 1

When you write cmd.exe , that will start a new command prompt. You don't want that.

When you write @echo off , that means nothing will be printed on the screen after that point. That's what it means. That's what it does. That is why it looks like nothing is happening.

Something would be printed to the screen if you had a compilation error, but probably you don't.

If you want the command prompt window to stay around instead of disappearing, I believe there is an option in Windows to configure that, at least there was when I last used Windows, back in the mists of time.

Answer 2

this worked for me. I think it does what you were looking to do.

This is the code I suggest for the .bat file:

cd C:\Users\John\JavaApps\folderThatContains.java //points terminal to folder

javac Main.java  //This compiles .java in said folder

cmd /K "java Main" //cmd /K prevents terminal from quitting after "java Main"