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Scala语法理解_ *和类型*

[英]scala syntax understanding _* and type*

I am having some difficulty in understanding this syntax: 我在理解此语法时遇到一些困难:

(as: List[A]) =>    val h = insert(e, as: _*)}

and

def insert(h: H, as: A*): H = as.foldLeft(h)((hh, a) => insert(a, hh))

What do _* and A* mean? _*A*是什么意思?

Thanks. 谢谢。

A* is an argument define as a vararg, it's equivalent to A... in Java. A*是一个定义为vararg的参数,它等效于Java中的A...

Exemple : 范例:

scala> def f(i: Int*) = i.length
f: (i: Int*)Int

scala> f(1,2,3)
res50: Int = 3

:_* is a transformer that allow to transform a param of type List into a vararg. :_*是一个转换器,可以将List类型的参数转换为vararg。

Exemple : 范例:

scala> f(List(1,2,3):_*)
res51: Int = 3
def insert(h: H, as: A*): H = as.foldLeft(h)((hh, a) => insert(a, hh))

A* represents a vararg : you can supply as many As as you wish to the method A *代表可变参数:您可以根据需要提供任意数量的方法

(as: List[A]) =>    val h = insert(e, as: _*)}

in this case a Sequences is converted to a vararg parameter ( a single list is converted into n single arguments having the type of A). 在这种情况下,序列将转换为vararg参数(单个列表将转换为n个类型为A的单个参数)。

sometimes this is necessary, imho it doesnt change too much on the conceptual level (as you still can invoke fold , map etc on both) 有时这是必要的,恕我直言,它在概念层面上并不会改变太多(因为您仍然可以同时调用fold,map等)

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