[英]how to combine results of two different queries from one table mysql
I am using MySQL in phpMyAdmin, I have a table from which I am trying to get the following result as illustrated below: 我在phpMyAdmin中使用MySQL,我有一个表,试图从中获得以下结果,如下所示:
I have a table Rate structured as follows; 我有一个表Rate,结构如下:
+---------+-----------+-------+--------+---------+----------+
| EntryID | RegDate | Code | Buying | Selling | Averages |
+---------+-----------+-------+--------+---------+----------+
| 1 |2013-11-08 | USD | NULL | NULL | 0.814 |
+---------+-----------+-------+--------+---------+----------+
| 2 |2013-11-08 | GBP | NULL | NULL | 0.114 |
+---------+-----------+-------+--------+---------+----------+
With the primary key as EntryID I am trying to get the output as shown below; 使用主键作为EntryID,我试图获得如下所示的输出;
+-----------+-------+-------+
| RegDate | USD | GBP |
+-----------+-------+-------+
|2013-11-08 | 0.814 | 0.114 |
+---------+---------+-------+
SELECT RegDate,
SUM(CASE WHEN Code='USD' THEN Averages ELSE 0 END) as USD,
SUM(CASE WHEN Code='GBP' THEN Averages ELSE 0 END) as GBP
FROM T
GROUP BY RegDate
SELECT USD.RegDate, USD.Averages as USD,
GBP.Averages as GBP From
(SELECT RegDate, Averages
From Table1 where Code = 'USD') USD
Inner join
(SELECT RegDate, Averages
From Table1 where Code = 'GBP') GBP
ON USD.RegDate = GBP.RegDate
You can simply JOIN
the table with itself, use the table once for each currency you need; 您可以简单地将表本身与
JOIN
,为所需的每种货币使用一次表;
SELECT usd.RegDate, usd.averages USD, gbp.averages GBP
FROM Table1 usd
JOIN Table1 gbp
ON usd.regdate = gbp.regdate
AND usd.code = 'USD'
AND gbp.code = 'GBP';
An SQLfiddle to test with . 要使用进行测试的SQLfiddle 。
Note that this query assumes that each currency exists exactly once per date to give a good result, if that's not the case, you should add that to your sample data. 请注意,此查询假定每种货币每个日期恰好存在一次,以提供良好的结果,如果不是这种情况,则应将其添加到样本数据中。
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