返回方括号和斜杠之间的字符串

Question

How to return string/values between square brackets and slashes inside like :

var valueX = "[/This is Value/]"

After catch, I need result : This is Value.

Thanks for your help.

Answer 1

Using replace :

'[/This is value/]'.replace(/\[\/(.*?)\/\]/, '$1'); // "This is value"

Use the global flag ( //g ) to replace all occurences :

'[/a/] [/b/] [/c/] [//]'.replace(/\[\/(.*?)\/\]/g, '$1'); // "a b c "

Answer 2

Use a Regular Expression :

var valueX = "[/This is value/]";
valueX.replace(/^\[\/(.*)\/\]$/, '$1');

Breaking it down, ^ matches the start of the line. \\[\\/ matches the initial [/ ; the backslashes are to stop them being interpreted as special characters. (.*) means match zero or more * of any character . and save it as a group () . \\/\\] is the final /] , and $ matches the end of the line. The $1 in the replacement string tells it to use the first matched group, in our case the zero or more of any character.