[英]Mysql Select some random rows and plus one specific row
I have a quiz system which questions have multiple choises. 我有一个测验系统,问题有多个选择。
I want to show the right answer plus four more wrong choices. 我想表明正确的答案加上四个错误的选择。 Totally I must have five choices. 我必须有五个选择。
Table choices 表格选择
id | choice | questionid | correct
---+--------+------------+--------
1 | choice1| 1 | false
2 | choice2| 1 | false
3 | choice3| 1 | false
4 | choice4| 1 | false
5 | choice5| 1 | true
6 | choice6| 1 | false
7 | choice7| 1 | false
8 | choice8| 1 | false
Table may be extended... 表格可能会延长......
Now I want to select four wrong answers and the correct answer to list below the question. 现在我想选择四个错误答案,并在问题下方列出正确答案。 And for each user sees the question choices should be different. 并且对于每个用户看到的问题选择应该是不同的。
How can I query the table for this result? 如何在表中查询此结果? I do not want to make two queries and bind them in an array like below: 我不想做两个查询并将它们绑定在如下所示的数组中:
SELECT *
FROM `choices`
WHERE questionid = :qid AND correct = true
SELECT *
FROM `choices`
WHERE questionid = :qid AND
correct = false AND
id IN(
SELECT id
FROM `choices`
ORDER BY RAND()
LIMIT 4
)
Instead it should be done with one step I guess. 相反,它应该完成一步我想。
SELECT *
FROM `choises`
WHERE questionid = :qid
ORDER BY correct DESC, RAND()
LIMIT 5
Assuming correct
is some sort of int. 假设correct
是某种int。 Otherwise you might need to change DESC
to ASC
. 否则,您可能需要将DESC
更改为ASC
。
You can 'shuffle' the 5 results using one more ORDER BY RAND()
like this: 您可以使用另外一个ORDER BY RAND()
来“混乱”5个结果,如下所示:
SELECT * FROM (
SELECT *
FROM `choises`
WHERE questionid = :qid
ORDER BY correct DESC, RAND()
LIMIT 5
) as t
ORDER BY RAND()
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