[英]show data by dates mysql
I have 3 mysql tables with data on the products with timestamp categorized by serial numbers. 我有3个mysql表,其中按时间戳将产品数据按序列号分类。
i would like to show how many distinct serial number entries are in each table by date. 我想按日期显示每个表中有多少个不同的序列号条目。
Table 1: 表格1:
serial timestamp
1 7/7/13
2 7/7/13
3 7/8/13
4 7/9/13
5 7/9/13
6 7/9/13
Table 2: 表2:
serial timestamp
1 7/6/13
2 7/7/13
3 7/8/13
4 7/9/13
table 3: 表3:
serial timestamp
1 7/9/13
2 7/10/13
3 7/10/13
output should be this: 输出应该是这样的:
date table1 table2 table3
7/6/13 0 1 0
7/7/13 2 1 0
7/8/13 1 1 0
7/9/13 3 1 1
7/10/13 0 0 2
Total 6 4 3
looking for the most elegant way to do this and display this in html via PHP. 寻找最优雅的方式来做到这一点,并通过PHP在html中显示。 need to start the output table with the earliest date in the 3 tables and end with the latest date in the 3 tables.
需要以3个表中最早的日期开始输出表,并以3个表中的最新日期结束输出表。
You will have to first merge all the data into one derived table and then pivot that table: 您将必须首先将所有数据合并到一个派生表中,然后再旋转该表:
SELECT timestamp,
COUNT(CASE WHEN tableNumber = 1 THEN tableNumber END) table1Total,
COUNT(CASE WHEN tableNumber = 2 THEN tableNumber END) table2Total,
COUNT(CASE WHEN tableNumber = 3 THEN tableNumber END) table3Total
FROM (
SELECT timestamp, 1 tableNumber FROM table1
UNION ALL
SELECT timestamp, 2 FROM table2
UNION ALL
SELECT timestamp, 3 FROM table3
) c
GROUP BY timestamp
Output: 输出:
| TIMESTAMP | TABLE1TOTAL | TABLE2TOTAL | TABLE3TOTAL |
|---------------|-------------|-------------|-------------|
| July, 06 2013 | 0 | 1 | 0 |
| July, 07 2013 | 2 | 1 | 0 |
| July, 08 2013 | 1 | 1 | 0 |
| July, 09 2013 | 3 | 1 | 1 |
| July, 10 2013 | 0 | 0 | 2 |
Optionally add WITH ROLLUP
after the GROUP BY
to show the totals. (可选)在
GROUP BY
之后添加WITH ROLLUP
以显示总计。
Use COUNT
and GROUP BY
使用
COUNT
和GROUP BY
SELECT
`timestamp`
COUNT( * ) as numEntries
FROM
tbl
GROUP BY
`timestamp`
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