[英]jQuery placing .each() functions inside a .click() function
The .each()
functions inside the .click()
are not running. 的
.each()
内的功能.click()
没有运行。 I do not know how to structure them to make it syntactically correct so jQuery will recognize and run them. 我不知道如何构造它们以使其在语法上正确,因此jQuery将识别并运行它们。
I tried tacking them on before the closing });
我试图在结束之前解决这些问题
});
but I either didn't do it right or that isn't how it's done. 但我要么做得不好,要么做得不好。 I tried Googling but other than my topic title I was at a loss for what to search.
我尝试了Google搜索,但是除了主题标题之外,我对搜索内容一无所知。 I did try jquery function inside function but that turned out to be a lost cause.
我确实尝试过在函数内部使用jquery函数,但事实证明这是一个丢失的原因。
EDIT: I have managed to get the first one to fire properly ( //POST specials
) however, the second one still isn't working. 编辑:我已经设法使第一个正确触发(
//POST specials
),但是,第二个仍然无法正常工作。 I even tried to put the extras POST
inside the .ajax()
of the specials
and it didn't work. 我甚至试图把
extras POST
里面.ajax()
的的specials
,并没有奏效。
$('.class').find('#button').click(function() {
//all kinds of variables here
var dataString = {//variables:variables}
console.log(dataString);
$.ajax({
type: "POST",
url: "classes/reserve.php",
data: dataString,
cache: false,
success: function(html)
{
//POST specials
$('#specialscheck input:checked').each(function() {
var reservation = $('#reservation').val();
var special = parseInt($(this).attr('id'));
dataString = {reservation:reservation, special:special};
console.log(dataString);
$.ajax({
type: "POST",
url: "classes/insert_specials.php",
data: dataString,
cache: false,
success: function(html)
{
//$('.unitinfolist').html(html);
}
});
});
//POST extras
$('#extrascheck input:checked').each(function() {
var reservation = $('#reservation').val();
var extra = parseInt($(this).attr('id'));
dataString = {reservation:reservation, extra:extra};
console.log(dataString);
$.ajax({
type: "POST",
url: "classes/insert_extras.php",
data: dataString,
cache: false,
success: function(html)
{
//$('.unitinfolist').html(html);
}
});
});
}
});
});
You should move the .each up into the success
function of the jquery post, or set its async: false
, to follow this pattern. 您应该将.each上移到jquery帖子的
success
函数中,或将其async: false
设置为遵循此模式。
$.ajax({
type: 'POST',
url: url,
data: data,
success: success,
dataType: dataType,
async:false
});
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