如何返回启动我的应用程序的应用程序

Question

Background:

My app (I will call it " A ") can be started from an intent. If a specific URL is clicked A is opened.

A has a custom navigation, so the back button does not always override super.onBackPressed() or finish() it.

The problem:

After opening A from another app lets say the email app (I will call it " E "), A can not come back to E . If I click the "tasks" button, where the user can see the name, icon, and a thumbnail of the current running apps, I can see that E (icon and name) has as thumbnail A , not E . When I click on it I go to A , and cannot come back to E .

The question:

Is there a way to come back to E from A ? Should I track the activity stack to come back to it whenever I want? I know that I can not force close an application, but could I open the A from E closing E before A is open? Is there a way to specify this behaviour on the intent?

Thanks in advance.

Answer 1

I found a solution that is working.

I check if the Activity of A comes from E , in this case I clear the Activity Stack and relaunch A .

if(comesFromE()){
    Intent i = getBaseContext().getPackageManager().getLaunchIntentForPackage(getBaseContext().getPackageName());
    i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
    startActivity(i);
    finish();
}

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