如何通过非常规命名的字段将CakePHP中的模型关联起来？

Question

I have two tables with field username in both. How i can specify field name for both local and foreign table?

I want CakePHP will do something like

ON (`T1`.`username` = `T2`.`username`)`

in result. Without any changes tables will be joined with following condition:

ON (`T1`.`id` = `T2`.`t1_id`)`

Setting 'foreign_key' = 'username' property is not enough because it will produce query like this:

ON (`t1`.`id` = `t2`.`username`)`

I have two solutions. First one is use 'join' property and join table on the fly. In such case i can set both local and foreign field. But if i need to join more tables to that one, joined manually, i can't use contain anymore i need to write following joins manually even if that associations was set correctly. So i need to write long join definitions every time instead just use 'contain' => array('T1', 'T2', 'T3')

Second is to set 'primary_key' of table to corresponding field. It can be done in model file or in runtime. In my case it can not be done in model because that table also have "correct" association by its 'id' field. Setup it runtime is the case but i dislike it because it's not obvious and looks like a hack.

When i ask this question i thought i missing something obvious but now i understand that CakePHP just can't do that. So i started a bounty hoping that somebody share solution. If not i will try to read cake sources and redefine model some of method to add ability to define local field near the 'foreign_key' in association definition.

Answer 1

ForeignKey false

To have an association which does not use the primary key of the related model in join conditions - the standard way to do that would be to use 'foreignKey' => false .

Ie whereas this association:

class Comment extends AppModel {
    public $belongsTo = array(
        'Profile' => array(
        )
    );
}

Will generate this sql:

SELECT ... LEFT JOIN profiles on ON (Profile.id = Comment.profile_id)

Specifying that a foreignKey isn't to be used like so:

class Comment extends AppModel {
    public $belongsTo = array(
        'Profile' => array(
            'foreignKey' => false
        )
    );
}

Will produce this (invalid) sql:

SELECT ... LEFT JOIN profiles on ON ()

From this point, the desired conditions can be specified using the conditions array key:

class Comment extends AppModel {
    public $belongsTo = array(
        'Profile' => array(
            'foreignKey' => false,
             'conditions' => array(
                 'Comment.username = Profile.username'
             ),
        )
    );
}

(Note that the conditions are defined as a string) resulting in:

 SELECT ... LEFT JOIN profiles on ON (Comment.username = Profile.username)

Answer 2

Update:

Just specify that you don't want to use a foreignKey, then specify the conditions (all within the association:

'foreignKey' => false and 'conditions' => 'Comment.username = User.username'

PS - probably a good idea moving forward to try not to be rude to the people helping you.

---

This is very clearly defined in the CakePHP book: http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#hasmany

class User extends AppModel {
    public $hasMany = array(
        'Comment' => array(
            'className' => 'Comment',
            'foreignKey' => 'user_id', // <---- THIS HERE you can define the foreign_key
            'conditions' => array('Comment.status' => '1'),
            'order' => 'Comment.created DESC',
            'limit' => '5',
            'dependent' => true
        )
    );
}

What is a Foreign Key? :

In the context of relational databases, a foreign key is a field in one table that uniquely identifies a row of another table.

Answer 3

Just a workaround that should work for your hasMany relationship when you want to retrieve a User and all his Comments

class User extends AppModel {
    public $hasMany = array(
        'Comment' => array(
            'finderQuery' => 'SELECT * FROM comments Comment 
                              LEFT JOIN users User 
                              ON Comment.username = User.username 
                              WHERE User.id = {__CakeID__}'
        )
    );
}

Hope it helps

Answer 4

I struggled with this exact problem for days and the solution that I found (not clearly addressed above) is: The hasMany must have 'foreignKey' => false while the belongsTo MUST ALSO have the 'foreignKey' => false and have the 'conditions' => 'Comment.username = User.username' . With the conditions as a string not assoc array. Like so:

// Profile
public $hasMany = array(
    'Comment' => array(
        'foreignKey' => false,
    )
);

// Comment
public $belongsTo = array(
    'Profile' => array(
        'foreignKey' => false,
        'conditions' => array('Profile.username = Comment.username')
    )
);

Answer 5

public $hasMany = array(
    'Comment' => array(
        'className' => 'T1',
        'foreignKey' => 'username',
        'dependent' => true
    )
);

Note that dependent true would delete all the T1's when T2's were deleted from within cake.