[英]Check for 6 or more consecutive numbers in a column in oracle sql
I need help with a query to identify unstructured data. 我需要查询帮助以识别非结构化数据。 I need to identify all the rows which have more than 6 consecutive numbers in their data.
我需要识别所有在数据中具有连续6个以上数字的行。 I know we can use regular expressions like ^[0-9] for the same.
我知道我们可以使用^ [0-9]这样的正则表达式。
For example: 例如:
I have a column named Address. 我有一列名为地址。 The address column may contain 6 or more consecutive numbers.
地址列可能包含6个或更多的连续数字。 I need to identify which rows contain more than 6 consecutive numbersi in them.
我需要确定哪些行包含超过6个连续numbersi。
675467 should be the output
67433232 should be the output
4453 should not be the output.
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