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C ++如何检查向量中存储的所有对象的元素是否具有相同的值?

[英]C++ how to check if an element of all objects stored in a vector have the same value?

For example I have an vector of objects and they all have attribute PointX so I want to check if all of them have the same value of PointX and if they have it should return true or false whatever. 例如,我有一个对象向量,它们都具有PointX属性,因此我想检查它们是否都具有相同的PointX值,以及是否具有返回的true或false。

So in a kind of pseudo-code: 所以用一种伪代码:

IF ( Object[1].getPointX() == Object[2].getPoint(x) == Object[3].getPoint(x) ){
      return true;
      }

The problem is that I have more than 55 objects so there has to be a way to compare them without writting them all individually. 问题是我有55个以上的对象,因此必须有一种比较它们的方法,而不必单独编写它们。 I know there must be with a for loop but still I have no idea. 我知道必须有一个for循环,但我仍然不知道。

thanks in advance. 提前致谢。

edit: @awesomeyi your suggestion seems the easiest and more adequate to my needs (I'm not saying the others are not but I think they are too complicated for a newb like me) but it's not working, even if Xpoints are all the same or different it always returns false. 编辑:@awesomeyi,您的建议似乎最容易满足我的需求(我不是说其他​​人不是,但我认为对于像我这样的新手来说它们太复杂了),但是即使Xpoints都一样,它也不起作用或不同,它总是返回false。 here's what i have: 这是我所拥有的:

bool allKilled(){ 
auto checkpointx = Invader[0].getIfActive(); 
for(int i = 0; i < 55; ++i){ 
if(Invader[i].getIfActive() != checkpointx){
 return false;}
}
}

the getIfActive() just returns if its true or false, and i want this method to return true if all Active (attribute of the object) of all objects are all false. 如果所有对象的所有Active(对象的属性)都为false,则getIfActive()仅返回其true或false,并且我希望此方法返回true。

Something like this: 像这样:

auto refx = Object[0].getPointX();
bool b = std::all_of(Object.begin(),
                     Object.end(),
                     [refx](TheTypeOfTHeElements& e) 
                     { return e.getPointX() == ref; });

Obviously you need to check that Objects is not empty. 显然,您需要检查Objects是否为空。

For loop? 循环?

auto checkpointx = Object[0].getPointX();
for(int i = 1; i < Object.size(); ++i){
    if(Object[i].getPointX() != checkpointx)
        return false;
}

I'd do it something like this: 我会做这样的事情:

template<typename Objects, typename Comparison>
bool is_all_same( Objects&& objects, Comparison&& comp ) {
  using std::begin; using std::end;
  auto&& b = begin(objects);
  auto&& e = end(objects);
  if (b == e)
    return true;
  auto&& first = *b;
  for( auto&& cur = std::next(first); cur != e; ++cur ) {
    if (!comp( first, cur ))
      return false;
  }
  return true;
}

use: 采用:

bool all_same_x = is_all_same( objs, []( Obj const& left, Obj const& right )->bool {
  return left.getPointX() == right.getPointX();
});

where objs is some container or range containing objects of type Obj . 其中objs是一些包含Obj类型Obj容器或范围。

The above code should work on all standard containers, C style arrays, custom containers that support the new for loops, and is close to optimal performance wise. 上面的代码应该在所有支持新的for循环的标准容器,C样式数组,自定义容器上工作,并且接近最佳性能。

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