[英]How do I search for term in separate mysql tables?
I'd like to search multiple columns and multiple tables. 我想搜索多个列和多个表。
I imported all my tables into sqlfiddle here: http://www.sqlfiddle.com/#!2/60689e/3 我在这里将所有表导入sqlfiddle: http ://www.sqlfiddle.com/#!2/60689e /3
What I'd like to select is user id, name_surname, avatar, from users table
Based on keyword, matching column "location" or "name_surname" in users table. 我想
user id, name_surname, avatar, from users table
选择user id, name_surname, avatar, from users table
基于关键字,匹配user id, name_surname, avatar, from users table
“ location”或“ name_surname”列。 This is relatively simple: 这是相对简单的:
SELECT u.name_surname,
u.avatar,
u.location
FROM users u
WHERE u.location LIKE :kwd
OR u.name_surname LIKE :kwd
The tricky part for me is querying table for matches in words_en table, which essentially should be queried against connections table where I actually can see which user is associated with which word... How do I do this last part escapes me. 对我来说,最棘手的部分是查询表中是否有words_en表中的匹配项 ,该表本质上应该在连接表中查询,在该表中我实际上可以看到哪个用户与哪个词相关联...我该怎么做最后一部分逃脱了。
So I probably need to: 所以我可能需要:
Thanks for looking. 感谢您的光临。 S.
S.
To get all users based on a search of the words_en
table would look something like SQL Fiddle : 要基于对
words_en
表的搜索来获取所有用户,看起来像SQL Fiddle :
SELECT u.id, u.name_surname, u.avatar
FROM users AS u
WHERE u.id IN
(
SELECT c.user_id
FROM connections AS c
JOIN words_en AS w
ON w.id = c.word_id
WHERE w.word = 'word1'
OR w.word = 'word2'
)
AND u.location LIKE '%Nunya%'
OR u.name_surname LIKE '%sandro%'
If you want to use the same search term for any of the three fields then use the following: 如果要对三个字段中的任何一个使用相同的搜索词,请使用以下内容:
SELECT u.name_surname, u.avatar, u.location
FROM users AS u
JOIN connections AS c ON c.user_id = u.id
JOIN words_en AS w ON w.id = c.word_id
WHERE (w.word LIKE '%word1%'
OR u.location LIKE '%word1%'
OR u.name_surname LIKE '%word1%')
AND u.privacy = 3
I hope I did not misunderstand your problem. 希望我不要误会你的问题。 Correct me if I am wrong some where.
如果我在某些地方做错了,请纠正我。
SELECT u.name_surname,
u.avatar,
u.location
FROM USERS AS U
INNER JOIN CONNECTIONS AS C
ON C.USER_ID = U.ID
INNER JOIN WORDS_EN AS W
ON W.ID = C.WORD_ID
AND W.WORD LIKE 'word1%'
I have hard coded word1 for example, you can also make INNER JOIN
of WORDS_EN
as LEFT JOIN
if you need all user information's having connections regardless of their words in WORDS_EN. 例如,我已对word1进行了硬编码,如果需要所有用户信息都具有连接能力,而不论WORDS_EN中的单词是什么,也可以将
WORDS_EN
INNER JOIN
WORDS_EN
为LEFT JOIN
。
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