[英]Struggling with PHP form processing
Can anyone help with a form problem that I just can't fathom? 有人可以解决我无法理解的表格问题吗? I have a group of checkboxes whose values I can't get to show up in the resulting mail.
我有一组复选框,其值无法显示在结果邮件中。
This is the method I'm using to set the variables: 这是我用来设置变量的方法:
$benefit01 = ($_POST['benefit_01']);
$benefit02 = ($_POST['benefit_02']);
$benefit03 = ($_POST['benefit_03']);
$benefit04 = ($_POST['benefit_04']);
$benefit05 = ($_POST['benefit_05']);
$benefit06 = ($_POST['benefit_06']);
$property = addslashes($_POST['property']);
$owner = addslashes($_POST['owner']);
$mainHeating = addslashes($_POST['Heating_mainHeating_answer']);
$boiler_working = addslashes($_POST['boiler_working']);
$boiler_age = addslashes($_POST['boiler_age']);
$postcode = addslashes($_POST['postcode']);
$address1 = addslashes($_POST['address1']);
$address2 = addslashes($_POST['address2']);
$address3 = addslashes($_POST['address3']);
$city = addslashes($_POST['town']);
$county = addslashes($_POST['county']);
$name = addslashes($_POST['firstName']);
$surname = addslashes($_POST['surname']);
$email = addslashes($_POST['email']);
$phone = addslashes($_POST['phonenum']);
$type = addslashes($_POST['type']);
$time = $_POST['time'];
$src = $_POST['urlsrc'] ;
$benefits = $benefit01." ".$benefit02." ".$benefit03." ".$benefit04." ".$benefit05." ".$benefit06;
$address = $address1." ".$address2;
$note = "Benefits: ".$benefits.". Property Type: ".$property.". Home Owner: ".$owner.". Type of Heating: ".$mainHeating.". Boiler Working: ".$boiler_working.". Boiler Age: ".$boiler_age.". Timescales: ".$time.". Address Line 3: ".$address3;
So the "benefits" are checkboxes. 因此,“好处”是复选框。 I had tried naming them all the same to create an array then imploding the values but that didn't work either.
我曾尝试将它们全部命名为相同的名称,以创建一个数组,然后内插值,但这也不起作用。 Ultimately this data is sent to a dbase which is why most of the info is dumped into a $note variable.
最终,这些数据被发送到数据库,这就是为什么大多数信息都被转储到$ note变量中的原因。
I don't know much about this and have taken this example from a working (albeit simplified) form. 我对此了解不多,并从一个有效的形式(尽管简化了)中举了这个例子。 Any assistance appreciated.
任何帮助表示赞赏。
** Small sample of the form added below: **以下表格中的小样:
<input name="ctl00_chkBenefit" type="checkbox" id="benefit_01" class="checkbox-benefit" value="Child Tax Credit" />
Child Tax Credit (where the relevant income is £15,860 or less) 儿童税收抵免(相关收入为£15,860或以下)
<input name="ctl01_chkBenefit" type="checkbox" id="benefit_02" class="checkbox-benefit" value="State Pension Credit" />
State Pension Credit 国家养老金信贷
Is your checkbox's HTML like this? 您的复选框的HTML是这样的吗?
<input type="checkbox" name="benefit_01" value="Benefit 01" /> Benefit 01
Then if that checkbox will be checked by user, $_POST['benefit_01']
will be the value of that checkbox - Benefit 01 . 然后,如果该复选框将由用户选中,则
$_POST['benefit_01']
将是该复选框的值$_POST['benefit_01']
01 。
If it will be not checked, $_POST['benefit_01']
will be not set. 如果未选中,则不会设置
$_POST['benefit_01']
。
EDITED 1: 编辑1:
And that all you should have in <form>
, with setted method and action: 并且您应该在
<form>
拥有所有内容,并具有设置的方法和操作:
<form action="index.php" method="post">
<input name="ctl00_chkBenefit" type="checkbox" id="benefit_01" class="checkbox-benefit" value="Child Tax Credit" />
</form>
EDITED 2: 编辑2:
You have different name
for that checkboxes. 您为该复选框使用其他
name
。 You used in your $_POST
theirs id
, not name
. 您在
$_POST
使用了他们的id
,而不是name
。
Change your code to this: 将代码更改为此:
$benefit01 = ($_POST['ctl00_chkBenefit']);
$benefit02 = ($_POST['ctl01_chkBenefit']);
$benefit03 = ($_POST['ctl02_chkBenefit']);
$benefit04 = ($_POST['ctl03_chkBenefit']);
$benefit05 = ($_POST['ctl04_chkBenefit']);
$benefit06 = ($_POST['ctl05_chkBenefit']);
Now it will work for 100% :) 现在它将适用于100%:)
First of all, 首先,
<input type="checkbox" name="benefits[]" value="one">
<input type="checkbox" name="benefits[]" value="2">
<input type="checkbox" name="benefits[]" value="III">
would create an array $_POST['benefits'] in PHP. 将在PHP中创建$ _POST ['benefits']数组。
Second, the variable will only contain the value if the checkbox is checked. 其次,如果选中此复选框,则变量将仅包含值。
Input checkboxes aren't set in $_POST if not checked by the user. 如果用户未选中输入复选框,则不会在$ _POST中设置输入复选框。 You can use
empty()
to determine if they're set and/or empty, and then set the value to the one you want to insert into the database. 您可以使用
empty()
来确定它们是否已设置和/或为空,然后将值设置为要插入数据库的值。
crate the input field name like this
<input type="checkbox" name="c[]" value="1">
<input type="checkbox" name="c[]" value="2">
<input type="checkbox" name="c[]" value="3">
<input type="submit" >
And PHP you can write like this- 而PHP您可以这样写:
<?php
$_POST['benefits']
?>
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