在嵌套列表中嵌套嵌套项[python]

Question

this is my nested list

list = [[01,"ny",100], [02,'jr",200], [03, "la", 300,"ny"]]

My Question is:

how to search for an item in the a specific position of nested list ex: i want to search for the item "ny" in the 2nd position of nested list means, my search has to match the item "ny" in only [][1] position it has to ignore "ny" in [3][3].

Answer 1

Using list comprehension:

>>> lst  = [[01,"ny",100], [02,"jr",200], [03, "la", 300,"ny"]]
>>> [sublst for sublst in lst if sublst[1] == "ny"]
[[1, 'ny', 100]]

To check whether ny exists, use any with generator expression:

>>> any(sublist[1] == "ny" for sublist in lst)
True
>>> any(sublist[1] == "xy" for sublist in lst)
False

BTW, don't use list as a variable name. It shadows builtin function list .

UPDATE : You can also use following as suggested by @DSM.

>>> "ny" in (sublist[1] for sublist in lst)
True

Answer 2

first, don't overwrite the list built-in.

second, you can use the filter built-in, to find all the matches:

list_ = [[01,"ny",100], [02,"jr",200], [03, "la", 300,"ny"]]
matches = filter(lambda element: element[1] == 'ny', list_)

Answer 3

exactly how you would think

list[0][1]

EDIT:

for inner in list:
    if inner[1] == 'ny':
        ...