第二个printf无法正常工作，需要帮​​助。 （C lang）

Question

What is the problem here? It prints the first printf but it doesn't print the next statement Help appreciated.

Code:

#include<stdio.h> 
#include<stdlib.h>

struct node
{
  int Data;
  struct node *Link;
};

//close struct
void insertAtEnd(struct node *Itcstd, int iData)
{
  while (Itcstd->Link != NULL )
    Itcstd = Itcstd->Link;

  Itcstd->Link = (struct node*) malloc(sizeof(struct node));
  Itcstd->Link->Link = NULL;
  Itcstd->Link->Data = iData;
} //close insertAtEnd

int main()
{
  struct node *EHead;

  EHead = (struct node*) malloc(sizeof(struct node));
  EHead->Link = NULL;
  EHead->Data = 4;

  printf("EHead link: %p Ehead Data: %d\n", EHead->Link, EHead->Data);
  insertAtEnd(EHead, 10);
  printf("EHead link: %p Ehead Data: %d\n", EHead->Link, EHead->Data);

  return 0;
} //close main

Answer 1

Actually it's a good code, it works for me perfectly. (I can see two lines.)

Answer 2

The code runs fine, without any memory issues.

The only point to mention is that the conversion specifier for printf() ing a pointer ( %p ) is defined for void * only. Having told the compiler to be pedantic (option -pedantic for gcc) it would have notified you about this.

So this

printf("EHead link: %p Ehead Data: %d\n", EHead->Link, EHead->Data);

shall be this

printf("EHead link: %p Ehead Data: %d\n", (void *) EHead->Link, EHead->Data);

This, btw, is one of the rare cases in C where casting can not be avoided.

Answer 3

code is elegant , and is working fine for me i checked it on windows (codeblocks MinGW gcc 4.7 , turbo c++) linux (gcc 4.8.1 ) and it works perfectly . which environment are you using ?