按字母顺序对关联数组/ javascript对象进行排序

Question

How do i order this object by the keys, Alphabetically?

I tried:

racks.sort();

The object racks is filled like this:

(Statdev is a string, and kartnr and bitnrk are integers)

racks[jPunten[i].STATDEV] = {
                            label: '',
                            punkt: [{
                            x: jPunten[i].KARTNR,
                            y: jPunten[i].BITNRK}]

Some Firebug output (i also noticed that in firebug the object IS ordered alphabetically):

racks
    []

DAY
    Object { punkt=[8], label=""}

label
    ""

punkt
    [Object { x="12", y="1"}, Object { x="12", y="2"}, Object { x="12", y="3"}, 5 meer...]

0
    Object { x="12", y="1"}

1
    Object { x="12", y="2"}

2
    Object { x="12", y="3"}

3
    Object { x="12", y="4"}

4
    Object { x="12", y="5"}

5
    Object { x="12", y="6"}

6
    Object { x="12", y="7"}

7
    Object { x="12", y="8"}

LSF01
    Object { punkt=[1], label=""}

label
    ""

punkt
    [Object { x="1", y="10"}]

0
    Object { x="1", y="10"}

x
    "1"

y
    "10"

Answer 1

In JavaScript impossible to sort object properties by keys. If you need it, you can put to array all keys of object, to sort them and then work with properties in desired order.

Answer 2

Try this:

sort = function(obj, comparator) {
    var array = [];
    for (var i in obj) {
        array.push([obj[i], i]);
    }
    array.sort(function(o1, o2) {
        return comparator(o1[0], o2[0]);
    });
    var newObj = {};
    for (var i = 0; i < array.length; i++) {
        newObj[array[i][1]] = array[i][0];
    }
    return newObj;
}

Answer 3

Do two arrays:

• one array for the keys
• the second associative array, using the key value pair, is actually an object.

// normal object notation

var personObject = {firstName:"John", lastName:"Doe"};
alert('personObject.firstName - ' + personObject.firstName);

// add to object using object-array notation, note: doing this will convert an array to an object

personObject["age"] = 46;

// array of keys, sorted

var keysArray = ["firstName", "lastName"];
keysArray[keysArray.length] = "age";
keysArray.sort();

// get object value, using array-object notation with array as key

alert('personObject[keysArray[0]] - ' + personObject[keysArray[0]]);