如何比较类的数据成员的名称而不是它们的值

Question

how to campare name of data member(not their value), sending as a argument from function. The example code is as follows.

class Example
{
  private:
   std::string value;

  public:
   void Set(const std:: string& MemberName)
   {
      if(MemeberName == value)
       {
         std::cout<<"Same Member Name";
       }
      else
      {
         std::cout<<"Not same Member name";
      }
   }
 ...
}

i did this way but not getting the required result. Thansks for the help

Answer 1

It should be

if(MemeberName == "value")
{
    std::cout<<"Same Member Name";
}
else
{
    std::cout<<"Not same Member name";
}

Answer 2

In case you want to find out whether it is the exactly same object, you might use the address, where it is stored:

#include <iostream>
using namespace std;

std::string g;

void foo(const std::string& arg)
{
    if (&arg == &g)                                        // compares addresses
        std::cout << "same object" << std::endl;
    if (arg == g)                                          // compares values 
        std::cout << "same value" << std::endl;
}

int main() {
    g = "abc";
    foo(g);
    return 0;
}

Note that when you pass by reference, you are actually working with the same object (no copy is being created) and thus when you use & operator you can retrieve the address of original object. This example prints both same object and same value .