[英]How to return an floating point array
I need a function that creates an array with some floating points. 我需要一个函数来创建带有一些浮点数的数组。
double * my_function( )
{
static double arr[10] = {20, 21, 22, 23, 24, 25, 26, 27, 28, 29};
return arr;
}
int main ()
{
double *first_pos;
int i;
first_pos = my_function();
for ( i = 0; i < 10; i++ )
{
printf( "%d", *(first_pos + i));
}
return 0;
}
This prints some "random" numbers. 这将打印一些“随机”数字。
I'm a confused about pointers/arrays! 我对指针/数组感到困惑!
Your pointer/array usage is fine. 您的指针/数组用法很好。
printf("%f", *(p + i));
Print doubles with the %f
specifier. 使用
%f
指示符将打印翻倍。 %d
is for ints. %d
用于整数。
I think it is %lf (long float) for doubles, and %f for normal floats 我认为双打是%lf(长浮点),普通浮点是%f
like this 像这样
first_pos = my_function();
for ( i = 0; i < 10; i++ ){
printf( "%lf\n", *(first_pos + i));
}
the output it gives me is 它给我的输出是
20.000000
21.000000
22.000000
23.000000
24.000000
25.000000
26.000000
27.000000
28.000000
29.000000
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.