[英]Extract a string between two words
I want to extract hash from string below which is e5e1af55bad959546ec7608cc8685fe67bc5426e
我想从下面的字符串中提取哈希,即
e5e1af55bad959546ec7608cc8685fe67bc5426e
$word1 = 'btih:';
$word2 = '&dn';
$magnet = "[magnet:?xt=urn:btih:e5e1af55bad959546ec7608cc8685fe67bc5426e&dn=The+Deadly+Game+2013+DVDRip+XviD-EVO+&tr=udp%3A%2F%2Ftracker.openbittorrent.com%3A80&tr=udp%3A%2F%2Ftracker.publicbt.com%3A80&tr=udp%3A%2F%2Ftracker.istole.it%3A6969&tr=udp%3A%2F%2Ftracker.ccc.de%3A80&tr=udp%3A%2F%2Fopen.demonii.com%3A1337]";
if(preg_match('/'.preg_quote($word1).'(.*?)'.preg_quote($word2).'/is', $magnet, $match)){
$upper = strtoupper($match['1']);
$generated = "http://torrage.com/torrent/".$upper.".torrent";
}
in above code, the hash are located between btih:
and &dn
can i know why my code doesnt work? 在上面的代码中,哈希位于
btih:
之间btih:
和&dn
我可以知道为什么我的代码不起作用吗?
You can use this lookaround based regex: 您可以使用这种基于环顾的正则表达式:
'/(?<=btih:)(.+?)(?=&dn=)/'
This means capture a string which is preceded by bith:
and followed by &dn=
这意味着捕获一个在
bith:
之前和&dn=
之后的字符串
Alternatively you can avoid lookbehind and use: 另外,您可以避免后顾之忧并使用:
'/:btih:\K(.+?)(?=&dn=)/'
Here \\K
is used to reset matched pattern. 这里
\\K
用于重置匹配的模式。
As an another alternative you can avoid lookahead
also and use: 作为另一种选择,您也可以避免
lookahead
并使用:
'/:btih:(.+?)&dn=/'
And use matched group #1
并使用匹配的
group #1
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