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用于查找在jQuery元素集中具有特定类的元素的索引的单线代码?

[英]A one-liner for finding the index of an element that has certain class within a jQuery set of elements?

I've got an arbitrary structure like this: 我有一个像这样的任意结构:

<h2>Foo</h2>
<p>Foo foo</p>
<p>Foofoo</p>

<h2>Bar</h2>

<h2 class=highlighted>Baz</h2>
<p>Baz</p>

<h2>Quux</h2>
<p>Quux quux</p>

In my JS i already have all h2 elements in a jQuery object: 在我的JS中,我已经在jQuery对象中包含了所有h2元素:

var $headings = $('h2');

Now i need to find which of those headings has the highlighted class. 现在,我需要找到那些突出显示类的标题。

So for the above structure the third heading is highlighted, so i expect to receive the answer 2 (JS counts from zero). 因此,对于上述结构,第三个标题将突出显示,因此我希望收到答案2(JS计数从零开始)。

I've managed to solve this task with: 我设法用以下方法解决了这个任务:

function foo($jQueryObject) {
  var number;
  $jQueryObject.each( function(index, element) {
    if ($(element).hasClass('highlighted')) {
      number = index;
      return false;
    }
  });
  return number;
}

Demo: http://jsbin.com/acaGeJi/1/ 演示: http//jsbin.com/acaGeJi/1/

But i'm sure there's a more elegant way, something like $headings.index('.highlighted'); 但是我敢肯定还有一种更优雅的方法,比如$headings.index('.highlighted'); . Can you please suggest it? 你能建议一下吗?

You can use the map method to get the index: 您可以使用map方法获取索引:

var index = $jQueryObject.map(function(i, e){
  return e.hasClass('highlighted') ? i : null;
})[0];

You can also use the index method, but then you have to get the element to look for first, so that means that you look for it twice: 您还可以使用index方法,但是随后必须先获取要查找的元素,这意味着您需要对其进行两次查找:

var index = $jQueryObject.index($jQueryObject.filter('.highlighted'));

You can use the $.index function 您可以使用$.index函数

var search = $( ".highlighted" );
alert( "Index: " + $( "h2" ).index( search ) );

This works for me: 这对我有用:

$('.highlighted').index('h2');

jsfiddle demo jsfiddle演示

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