得到一个字符串php正则表达式匹配

Question

here is my string

0 12 10 0 5 0 albert 126 al br t 881 alert 58 a lbr t 317 apart 251 al b rt 284 ambit 165 a lb rt 9 album 93 al br t 881 10 6 13 0 einstein 92 en stein 219 epstein 8 en stein 335 eastern 62 ens t ein 317 enshrin 13 en st ein 231 enseign 3 ens tei n 203 false albert einstein 154 albert einstein (al br t) einstein 1030 al br t einstein albert (en stein) 318 albert en stein albert epstein 134 albert epstein alert einstein 139 alert einstein

I need to get the value in between false and the number next to the words.. in the above case I require

... false albert einstein 154 ... => albert einstein

I tried the below regex match, but its not working. What am I missing here?

$matches=array();
preg_match('/false=([a-z]+)\[0-9]+/', $response, $matches);
echo $matches[1];

Answer 1

Try a pattern like this:

false\s*(.+?)\s*[0-9]+

This will match:

• false - the literal string false
• \\s* - zero or more whitespace characters
• (.+?) - one or more of any character, non-greedily, captured in group 1
• \\s* - zero or more whitespace characters
• [0-9]+ - one or more decimal digits

For example:

$input = 'false albert einstein 154';
preg_match('/false\s*(.+?)\s*[0-9]+/', $input, $matches);
echo $matches[1]; // 'albert einstein'

Answer 2

The following works for me:

$response = ".false albert einstein 154.";
$matches=array();
preg_match('/.*?false ([a-z\s]+) (?=[0-9]{3}).*/', $response, $matches);
echo $matches[1];