如何在c中增加2d char数组元素的大小

Question

char symbol[100][100];
for(i=0;i<n;i++)
    {
       printf("enter the symbol\n");
       scanf("%s",&symbol[0][i]);   
    }
strncat(&symbol[0][0],"1",1);

output for ex:- in symbol[0][0] i have entered 'a'

strncat(&symbol[0][0],"1",1);    

should give the output as a1 buti know the size of symbol[0][0] is 1 byte thats why itsshowing output only a how to increase the size of symbol[0][0] sothat it can show the desired output a1

Answer 1

Try this

strncat(symbol[0],"1",1);

int main()
{
    int i,n=1;
    char symbol[100][100];
    for(i=0;i<n;i++)
        {
           printf("enter the symbol\n");
           strcpy(symbol[0],"a");  
        }
    strncat(symbol[0],"1",1);
    printf(symbol[0]);
    return 0;
}

Make changes as required..:)..

Answer 2

a1 is composed of character a and character 1 . So if you'd like to have a matrix for double-characters wide symbol, you can declare a 3D array like

char symbol [100][100][2];

then

scanf("%c%c", &symbol[0][i][0], &symbol[0][i][1]);

BTW: Well, a single element , or symbol you referred, can be composed of elementary element or symbol of internal type of C/C++. So is a1 in your question a name of variable or the value?