使用AJAX返回json数组

Question

Here's the javascript:

var data = $('form#registration-form').serialize();
$.post(
'<?php echo $this->url('/register', 'do_register')?>',
function(data) {
 alert(data);
},
'json'
);

And here's the ending of the do_register() method:

if( $_REQUEST['format']=='JSON' ){
$jsonHelper=Loader::helper('json'); 
echo $jsonHelper->encode($registerData);
die;
}

The $registerData variable holds all the data I need. I want the function to return it after the ajax call. However, when I specify dataType: 'json' nothing is returned. Any suggestions?

Answer 1

I think your problem is in url

$.post(
'<?php echo $this->url("/register", "do_register"); ?>?format=JSON',
function(data) {
 alert(data);
},
'json'
);

Also you can use following line in php part to get json values

header('Content-Type: application/json');

Answer 2

I suppose problem is somewhere here:

'<?php echo $this->url('/register', 'do_register')?>', in using quotes.

Use double and single quotes:

"<?php echo $this->url('/register', 'do_register')?>", .

Answer 3

It's impossible to receive right suggestion with little description.

Y'd better to paste more php & javascript code, with much more context, thing to be simple.

And another suggestion, mixed coding is bad. separating the javascript and php with php template such as Smarty.

var data = $('form#registration-form').serialize();
$.post(
'<?php echo $this->url('/register', 'do_register')?>',
function(data) {
 alert(data);
},
'json'
);

this source file of above code is a php file ?

Debug with firebug to capture weather the ajax request sent or not

Answer 4

Why use JSON helper??

json_decode(string $json);
json_encode(mixed $value); //normally array...

it is built-in in php.