web.xml配置作为注释

Question

I am trying to start a basic example project that uses Vaadin together with Spring. How can I put such xml configuration:

 <context-param>
      <param-name>contextClass</param-name>
      <param-value>
        org.springframework.web.context.support.AnnotationConfigWebApplicationContext
      </param-value>
    </context-param>

   <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>com.app.config.AppConfig</param-value>
   </context-param>

   <listener>
     <listener-class>
       org.springframework.web.context.ContextLoaderListener
     </listener-class>
   </listener>

to such java based configuration:

    @WebServlet(value = "/*", asyncSupported = true)
    @VaadinServletConfiguration(productionMode = false, ui = MyVaadinUI.class,       widgetset = "com.rrd.mavenproject1.AppWidgetSet")
public static class Servlet extends VaadinServlet {
}

Answer 1

You can't. If you had a custom Servlet XxxListener , you could annotate it with @WebListener . In this case you are trying to load ContextLoaderListener which you have no control over.

Context parameters are global to the application and therefore can't be added to one single @WebServlet annotation.

What you might be looking for is the Servlet API's ServletContainerInitializer or Spring's WebApplicationInitializer to perform Java configuration.

In either of these, you will have access to the ServletContext where you can add context parameters and listeners . The strength of these classes is that you can create your Servlets, Filters, and Listeners from a Spring context.