argv [1] +1和argv [2]有什么区别

Question

I know this question is basic, I also newbie, so plz help me clear this problem:

I have this code:

int wmain(int argc, wchar_t *argv[])
{
    if (*argv[1] == L'-' && (!_wcsicmp(L"install", argv[1]+1)))
    {
        wprintf(L"You pressed: -install !");
    }
    else
    {
        wprintf(L"Unknown");
    }
}

It work OK, but if I replace to:

int wmain(int argc, wchar_t *argv[])
{
    if (*argv[1] == L'-' && (!_wcsicmp(L"install", argv[2])))
    {
        wprintf(L"You pressed: -install !");
    }
    else
    {
        wprintf(L"Unknown");
    }
}

It's break when run.

I don't know

• Why use argv[1]+1
• What difference between argv[1]+1 and argv[2] (I've used above).

Anyone explain for me, and give me document about wchar_t ???

Answer 1

argv [1] +1指向argv [1]字符串中的第二个字符，而argv [2]指向下一个字符串。

Answer 2

First, Why use argv[1]+1: --> _wcsicmp require POINTER, so you need pass: argv[1] + 1 or argv[2]

Second, What difference between argv[1]+1 and argv[2] (I've used above). : --> Do you see second argument of wmain: wchar_t *argv[] ? - This is mean POINTER to ARRAY (same same POINTER to POINTER).

Each argument separate by space. So, argv[1] is pointer point to second argument, argv[2] is pointer point to third argument. And, argv[1]+1 increase address in pointer by 1 (mean, that pointer will point to second character in second argument string)

Answer 3

argv[1] + 1 is a pointer to the second character in argv[1] while argv[2] is the third element (pointer to character) in argv .

argv[1] == *(argv + 1)
argv[2] == *(argv + 2)
argv[1] + 1 == *(argv + 1) + 1 != argv[2]