如何运行来自单独文件的PHP
[英]How to run PHP coming from a separate file
问题描述
I have a form thats action is another page. 
我有一个表单，多数民众赞成在动作是另一页。
<form class="indexSearch" action="search.php" method="post">
to keep my code neat I'm keeping all my PHP code in a separate file that I am including in the head of every page... 为了使代码保持整洁，我将所有PHP代码都保存在一个单独的文件中，该文件包含在每个页面的开头...
<head>
<?php include 'include/includes.php';?>
</head>
The problem I'm having is when the PHP code in the includes.php file runs, it echoes at the top left hand corner of the page I want it to appear on and I am confused about the best way to include it where I need it... 我遇到的问题是， includes.php文件中的PHP代码运行时，它在我希望它出现在页面的左上角回显，并且我对在需要的地方包括它的最佳方法感到困惑它...
Any help would be greatly appreciated. 任何帮助将不胜感激。
Thx 谢谢
Sorry just to update on my question which was a bit vague in the include file I intend to hold all functions / scripts etc... the particular code I am trying to output in this instance is a while loops from a mysqli query 对不起，我只是想更新我的问题，我打算保留所有函数/脚本等在包含文件中有点含糊...在这种情况下，我试图输出的特定代码是一个从mysqli查询中循环的循环
3 个解决方案
解决方案1
3 2013-11-18 12:09:20
不用在include php中执行回显，而是分配给一个变量，然后使用以下命令将其回显到所需的位置：
<?php echo $varname; ?>
解决方案2
0 2013-11-18 12:13:34
Put some conditions in your include.php 在include.php一些条件
you can use functions such as isset() , empty() to protect them to print that by default. 您可以使用isset() ， empty()来保护它们以默认情况下进行打印。
and my personal suggestion is that use require_once('include/include.php') ; 我的个人建议是使用require_once('include/include.php') ;
解决方案3
0 2013-11-18 12:13:59
<?php include 'include/includes.php'; ?>
In includes.php: define your values in to variable, 在includes.php中：将值定义为变量，
<?php $Variable = 'test check'; ?>
Now include your file where ever you want, after the inclusion of your includes.php you can able to retrive and print the value of $Variable . 现在，将文件包含在任何位置，在包含了includes.php您就可以检索并打印$Variable的值了。
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