Python RegEx帮助：将字符串拆分为数字，字符和空格

Question

I am trying to split my string into a list, separating by whitespace and characters but leaving numbers together.
For example, the string:

"1 2 +="  

would end up as:

["1", " ", "2", " " ,"+", "="]    

The code I currently have is

temp = re.findall('\d+|\S', input)  

This seperates the string as intended but does also remove the whitespace, how do I stop this?

Answer 1

Just add \\s or \\s+ to your current regular expression (use \\s+ if you want consecutive whitespace characters to be grouped together). For example:

>>> s = "1 2 +="
>>> re.findall(r'\d+|\S|\s+', s)
['1', ' ', '2', ' ', '+', '=']

If you don't want consecutive whitespace to be grouped together, then instead of r'\\d+|\\S|\\s' it would probably make more sense to use r'\\d+|\\D' .

Answer 2

You can use \\D to find anything that is not a digit:

\d+|\D

Python:

temp = re.findall(r'\d+|\D', input) 
//Output: ['1', ' ', '2', ' ', '+', '=']

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It would also work if you just used . since it'll match the \\d+ first anyway. But its probably cleaner not to.

\d+|.