编写一个程序，该程序生成10到100之间的10个随机整数的列表

Question

I am having trouble with the following assignment:

Write a program that generates a list of 10 random integers between 10 and 100. Your program should print the values followed by how many values were odd and how many were even.

Here is the code I have so far:

public static void main(String[]args)
{
  for(int i = 0; i<10; i++){
        System.out.println("Random number: " + (int)(Math.random() * 101 + 10));
        if((int)(Math.random() * 101 + 10) %2 == 0){
          System.out.println((int)(Math.random() * 101 + 10) + " even numbers were generated");}
        else
          System.out.println((int)(Math.random() * 101 + 10) + "odd numbers were generated");
        }
   }
}

Any help is appreciated, thanks!

Answer 1

for (int i = 0; i < 10; i++) {
    System.out.println((int) (Math.random() * (90 + 1)) + 10);
}

This will generated and print 10 random integers between 10 and 100. As for the odd and even part, you can divide the number by 2 and check for the remainder. I'll leave the rest to you.

Answer 2

This will generate 10 random integers between 10 and 100, perform the count of even and odd and finally display the counts.

public static void main(String[] args) {
  Random rnd = new Random(System.currentTimeMillis());
  int even = 0;
  int odd = 0;
  for (int i = 0; i < 10; i++) {
    int randomNumber = 10 + rnd.nextInt(91);
    System.out.println("Random number " + (1 + i)
        + ": " + randomNumber);
    if (randomNumber % 2 == 0) {
      even++;
    } else {
      odd++;
    }
  }
  System.out.println(even + " even numbers "
      + "were generated");
  System.out.println(odd + " odd numbers "
      + "were generated");
}