[英]How to print part of words in string by input using array in c?
The C program below print the third until last character of 80 words strings 下面的C程序打印第三个字符,直到80个字符串的最后一个字符
#include <stdio.h>
int main(void) {
char a[] = "computer";
char start = 3;
char length = 7;
printf("%.*s\n", length, a + start);
return 0;
}
the output : 输出 :
puter
how to write in c code for print "n" last character of string 如何用c代码写入字符串的最后一个字符“n”
ex: 例如:
string : "this computer" 字符串:“这台电脑”
n inputed by scanf ex: 5 n由scanf ex输入:5
it will print to console 它将打印到控制台
"puter" “帕特”
Change 更改
char start = 3;
char length = 7;
to 至
int start;
int length;
and do as follows; 并做如下; I used a pointer in this program.
我在这个程序中使用了一个指针。
#include <stdio.h>
#include <string.h>
int main(void) {
char a[] = "this computer";
int start;
int length;
char *ptr = a; // Initializing ptr with first element of string literal.
length = strlen(a); // Calculating the length of string literal
scanf("%d", &start);
if(start > length)
start = length;
ptr += length - start; // Adding the desired last number of elements/characters to be printed to the address ptr points to.
printf("%s\n", ptr);
return 0;
}
Input: 输入:
5
Output: 输出:
puter
In case the string, of which you're trying to print a substring is not hard-coded, you'll need to determine its length, too: 如果您尝试打印子字符串的字符串不是硬编码的,那么您还需要确定其长度:
char some_string[] = "this computer";
char *out_ptr = &some_string;
int length, offset;
length = strlen(some_string);
scanf("%d", &offset);
out_ptr += length - offset;
printf("%s", out_ptr);
This allows you to pour this into a neat little function: 这允许你把它倒入一个整洁的小功能:
void print_substr(char *str_ptr)
{
int offset, len = strlen(str_ptr);
scanf("%d", &offset);
if (offset > len) offset = len;
str_ptr += len - offset;
printf("%s\n", str_ptr);
}
And it's dead-easy to use, as you can see here, on this code-pad 在这个代码板上 ,你可以看到, 这很容易使用
Here's how I would do it: 我是这样做的:
void print_substring(const char *string, unsigned int start, unsigned int length)
{
const size_t len = strlen(string);
if(start >= len)
return;
if(start + length > len)
length = len - start;
for(; length != 0; --length)
putchar(string[start++]);
putchar('\n');
}
#include <stdio.h>
int main(void) {
char a[] = "computer";
char start = 3;
char length = 8;
int n;
scanf("%d",&n);
printf("%.*s\n", n,&a[length-n]);
return 0;
}
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