从函数返回迭代器给我一个奇怪的错误

Question

So I have my class named Client and it contains a list of strings. I want a method to get an iterator at the beginning and another at the end. So I have the following code:

iterator Client::getGustBegin() const { return _gustos.begin(); }
iterator Client::getGustEnd() const { return _gustos.end(); }

And in the Client.h it's like this:

    iterator getGustBegin() const;
    iterator getGustEnd() const;

Also _gustos is declared like this:

list<string> _gustos;

I'm using g++ compiler and it shows me this error:

error: invalid use of template-name 'std::iterator' without an argument list

In both of the lines in the Client.h. I have the map and list includes. I don't know why and I don't understand the error. What am I doing wrong?

Answer 1

A typedef is often a good thing:

class Client
{
   public:
   typedef std::list<std::string>::iterator gust_iterator;
   gust_iterator getGustBegin() const;
};


inline Client::gust_iterator Client::getGustBegin() const {
   return _gustos.begin();
}

In your case (as already pointed out) iterator is referring to std::iterator. (Hence, you gave another example for avoiding 'using nmaespace std')