简单的preg_replace替换锚文本

Question

Having issues wish a preg_replace function.

I am formatting a breadcrumb which the php is ioncubed so I am having to preg_replace to remove part of the breadcrumb.

I have a breadcrumb that looks like

<ul>
    <li><a href="mylink1.html">Link 1</a><i class="fa fa-angle-right"></i></li>
    <li><a href="mylink2.html">Link 2</a><i class="fa fa-angle-right"></i></li>
    <li><a href="mylink3.html">Link 3</a></li>
</ul>

What I want to do is completely remove

<li><a href="#">Link 2</a><i class="fa fa-angle-right"></i></li>

My Original thoughts were to just str_replace

<li><a href="#">Link 2</a><i class="fa fa-angle-right"></i></li>

with nothing however the link can vary depending on the language file loaded.

I then thought about preg_replace the content of the url as the href is constant however I have absolutley no experiance with PHP and all attempts I have tried give random responses.

I'm hoping someone can help with the preg_replace or even if there is a better way to remove the line.

So far Ive tried

$str = '<li><a href="mylink.php">Link 2</a></li>';

$preg_replace = preg_replace('<li><a href="mylink.php">(.*)','placeholder',$str);

echo $preg_replace;

Thanks

Answer 1

You have to bound your regex, typically with / . You also might want to include the closing tag or your regex will match more than you want

$preg_replace = preg_replace('/<li><a href="mylink\.php">(.*)<\/a>/','placeholder',$str);

I highly recommend http://regex101.com/ for learning more about regex and how to make them work.