在jquery中设置.css（）中的属性

Question

Hello guys probably i'm having a problem on setting property

transform: rotate(30deg) 

in my selector

$('.box1').css('left', x); 

I dont know where to add this line, can I put a variable in degrees? Thanks guys. I hope you can help me out fixing this.

Answer 1

Simply:

$('.box1').css({
    left: x,
    transform: 'rotate(30deg)'
});

Or:

$('.box1').css('left', x).css('transform', 'rotate(30deg)');

JSFiddle demo .

Answer 2

用这个

$('.box1').css('left', x).css('transform', 'rotate(30deg)')