如何在不使用泛型的情况下在ServiceStack中注册类型

Question

It is possible to register a type in ServiceStack Container using a object instance and its Type?

 object type_to_be_registered;
 Type type = type_to_be_registered.GetType();

The "type_to_be_registered" implements some interfaces and I want to register the "type_to_be_registered" for its interfaces. I can get the interfaces using the following code:

Type[] interfaces = type.GetInterfaces();

But how can I register the object for each of its implemented interfaces, since I do not know (at compiling time) the type of the "type_to_be_registered" object and its interfaces??

Answer 1

Please read the docs for IOC in ServiceStack . Here are some examples that registers using a runtime type:

container.RegisterAutoWiredType(typeof(MyType));
container.RegisterAutoWiredType(typeof(MyType),typeof(IMyType));
container.RegisterAutoWiredTypes(typeof(MyType),typeof(MyType2),typeof(MyType3));

You can just register the instance as a Singleton with:

container.Register(instance);

As well as use the CreateInstance() extension method to create an instance from a type:

container.Register(type.CreateInstance());

If you want to register the instance of a different type, you can use reflection to call the generic method, eg:

public static class ContainerExtensions
{
    public static Container Register(this Container container, 
        object instance, Type asType)
    {
        var mi = container.GetType()
            .GetMethods()
            .First(x => x.Name == "Register" 
                     && x.GetParameters().Length == 1 
                     && x.ReturnType == typeof(void))
            .MakeGenericMethod(asType);

        mi.Invoke(container, new[] { instance });
        return container;
    }
}

Then you can register it with:

container.Register(instance, type(AlternateType));