[英]Customizing layout to sfWidgetFormDoctrineChoice disable checkbox
Good morning, 早上好,
In Symfony 1.4, 在Symfony 1.4中,
I tried to do what is explained here : Customizing layout to sfWidgetFormDoctrineChoice 我尝试执行此处说明的操作:将布局自定义为sfWidgetFormDoctrineChoice
But it doesn't work. 但这是行不通的。 Instead of adding a thumbnail, I just want to hide the
<li>
before the input, and in some condition disable/hide the checkbox input but show the label anyway . 除了添加缩略图之外, 我只想在输入之前隐藏
<li>
,并在某些情况下禁用/隐藏复选框输入,但仍然显示标签 。
When I add the renderer without argument, I get this error : 当我添加不带参数的渲染器时,出现以下错误:
sfWidgetFormMySelectCheckbox requires the following options: 'choices'.
Here is my formatter code : 这是我的格式化程序代码:
class sfWidgetFormMySelectCheckbox extends sfWidgetFormSelectCheckbox
{
public function configure($options = array(), $arguments = array())
{
parent::configure($options, $arguments);
}
protected function formatChoices($name, $value, $choices, $attributes)
{
.....
// new
$inputs[$id] = array(
'input' => sprintf('| test | %s',
$this->renderTag('input', array_merge($baseAttributes, $attributes))
),
'label' => $this->renderContentTag('label', self::escapeOnce($option), array('for' => $id)),
);
}
return call_user_func($this->getOption('formatter'), $this, $inputs);
}
}
And now the form where I call it : 现在是我称之为的表格:
$this->setWidget('aaa', new sfWidgetFormDoctrineChoice(array(
'model' => 'Aaa',
'expanded' => true,
'multiple' => true,
'add_empty' => false,
'query' => $query,
'renderer' => new sfWidgetFormMySelectCheckbox()
)));
Thanks for your help ! 谢谢你的帮助 !
According to the docs you have to pass the choices
option to the renderer
object. 根据文档,您必须将
choices
选项传递给renderer
对象。 Try something like this: 尝试这样的事情:
$this->setWidget('aaa', new sfWidgetFormDoctrineChoice(array(
'model' => 'Aaa',
'expanded' => true,
'multiple' => true,
'add_empty' => false,
'query' => $query,
)));
$this->widgetSchema['aaa']->setOption('renderer', new sfWidgetFormMySelectCheckbox(array(
'choices' => new sfCallable(array($this->widgetSchema['aaa'], 'getChoices'))
)));
So basically you want the renderer object get the choices from the parent widget. 因此,基本上,您希望渲染器对象从父窗口小部件中获得选择。 To do that you have to pass a
sfCallable
object which takes an array
as the first argument in which you pass the instance of your parent widget and the name of the function getChoices
. 为此,您必须传递一个
sfCallable
对象,该对象将array
作为第一个参数,并在其中传递父窗口小部件的实例和函数getChoices
的名称。
Remember also that the expanded
option is not used when you override the renderer
. 还要记住,当您覆盖
renderer
时,不会使用expanded
选项。
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