简体   繁体   English

使用Gson解析JSON数字数组

[英]Parse JSON number array using Gson

This is the JSON string I want to parse with Gson. 这是我要与Gson解析的JSON字符串。 I would like to quick and simple to parse it. 我想快速简单地解析它。

{
    "values": [
        [
            1, 
            1, 
            0, 
            0, 
            0, 
            0, 
            11, 
            0.09090909090909091
        ], 
        [
            [
                0, 
                0, 
                0, 
                0, 
                0, 
                1, 
                0
            ], 
            [
                0, 
                0, 
                0, 
                0, 
                0, 
                1, 
                0
            ], 
            [
                0, 
                0, 
                0, 
                0, 
                0, 
                0, 
                0
            ], 
            [
                0, 
                0, 
                0, 
                0, 
                0, 
                0, 
                0
            ], 
            [
                0, 
                0, 
                0, 
                0, 
                0, 
                0, 
                0
            ], 
            [
                0, 
                0, 
                0, 
                0, 
                0, 
                0, 
                0
            ], 
            [
                0, 
                0, 
                0, 
                0, 
                0, 
                11, 
                0
            ], 
            [
                0, 
                0, 
                0, 
                0, 
                0, 
                0.09090909090909091, 
                0
            ]
        ]
    ]
}

but I don't know how to write the parsing code with Gson. 但是我不知道如何用Gson编写解析代码。 Best result is if I can extract List from the parsed object. 最好的结果是我是否可以从解析的对象中提取List。

Is any possible that i Write a class like that. 我有可能写这样的课程吗?

class Value  
{  
    @SerializedName("0")   
    List<Float> value1;   
    @SerializedName("1")   
    List<Integer> value2;   
    ...........   
 } 

Thanks for everyone to help me. 谢谢大家的帮助。

This is the fastest way I know to get the info you need in the most usable format for you. 我知道这是最快的方式,它以最实用的格式为您获取所需的信息。

Your JSON is made of a list that contains list1 - a list of double - and list2, a list of list of double. 您的JSON由包含list1(一个双精度列表)和list2(一个双精度列表列表)的列表组成。 Assuming that you want to parse exactly the example you provided with, this is a self contained class that you can use. 假设您想完全解析所提供的示例,则这是一个可以使用的自包含类。

If you need mode details on how it works, feel free to ask. 如果您需要有关其工作方式的详细信息,请随时询问。

package stackoverflow.questions;

import java.lang.reflect.Type;
import java.util.List;

import stackoverflow.questions.Test.Wrapper;

import com.google.gson.*;
import com.google.gson.reflect.TypeToken;

public class Q20118749 {

   /**
    * @param args
    */
   public static void main(String[] args) {
      String json = "{\"values\":[[1,1,0,0,0,0,11,0.09090909090909091],[[0,0,0,0,0,1,0],[0,0,0,0,0,1,0],[0,0,0,0,0,0,0],[0,0,0,0,0,0,0],[0,0,0,0,0,0,0],[0,0,0,0,0,0,0],[0,0,0,0,0,11,0],[0,0,0,0,0,0.09090909090909091,0]]]}";

      JsonElement je = new JsonParser().parse(json);
      JsonArray list = je.getAsJsonObject().get("values").getAsJsonArray(); // to get rid of the value part

      Type listType1 = new TypeToken<List<Double>>() {}.getType();
      Type listType2 = new TypeToken<List<List<Double>>>() {}.getType();

      Gson g = new Gson();

      List<Double> listOfDouble = g.fromJson(list.get(0), listType1);
      List<List<Double>> listOfListOfDouble = g.fromJson(list.get(1), listType2);

      System.out.println(listOfDouble);
      System.out.println(listOfListOfDouble);
   }

}

This is my execution: 这是我的处决:

[1.0, 1.0, 0.0, 0.0, 0.0, 0.0, 11.0, 0.09090909090909091]
[[0.0, 0.0, 0.0, 0.0, 0.0, 1.0, 0.0], [0.0, 0.0, 0.0, 0.0, 0.0, 1.0, 0.0], [0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0, 0.0, 11.0, 0.0], [0.0, 0.0, 0.0, 0.0, 0.0, 0.09090909090909091, 0.0]]

If your data changes, of course, you have to change this code according. 当然,如果您的数据发生更改,则必须根据此代码进行更改。

Use this code. 使用此代码。

public class MyObject{
  @SerializedName("values")
  private Values[] mValues;

  public Value[] getLoc() {
return mvalues;
}
}

public class Values{
 @SerializedName("0")
 private Zero[] mZero;

 @SerializedName("1")
 private One[] mOne;

 public Zero[] getZero() {
return mZero;
 }

 public Value[] getOne() {
return mOne;
 }
}

public class Zero{
 @SerializedName("0")
 private zint zero;

 public  int getZeroValue() {
    return zero;
 .........
 }

}

like this you have to write 像这样你必须写

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM